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2 years ago

8

Write an expression that represents the area of a rectangle with the length 6a to the power of 2 b and the width of 3ab ( for an

y rectangle with the length \" l \" and the width w, A=lw. )

1 answer:

brilliants [131]2 years ago

5 0

L = 6 a^2 b, W = 3 a b
The area of a rectangle:
A = L x W =
= 6 a² b · 3 a b = 18 a³ b²

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За(2b + 5c)<br><br> I need help

ch4aika [34]

Hey! Your answer would be = 6ab+15ac

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3 years ago

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OleMash [197]

Answer:

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3 years ago

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goblinko [34]

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kow [346]

Let a,b,c be the sides of the triangle. Make c the longest side. The value of a and b doesn't matter.
a = 9
b = 40
c = 41

The value of a^2+b^2 is
a^2+b^2 = 9^2+40^2 = 1681

The value of c^2 is
c^2 = 41^2 = 1681

Because a^2+b^2 = c^2 for these values, this means that we have a right triangle.

Answer is choice D

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2 years ago