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zimovet [89]
3 years ago
9

What are 5 ways that graph can be misleading ?

Mathematics
2 answers:
Elza [17]3 years ago
3 0
<h3>Hello there hope you having a good day :)</h3><h3>. The axis are plotted to a scale that make people think there is more or less    value.</h3><h3>. The graph overall may represent a rather insignificant subject.</h3><h3>.  The graph overall may make something important appear rather small.</h3><h3>.  The graph may represent factors without pointing out other important factors.</h3><h3>. If there is no x and y axis.</h3><h3>Hopefully this helps you. Another one would be if it doesn't start with 0.</h3>

Nata [24]3 years ago
3 0

There are many ways that graphs can be misleading. Depending on how you set up your graph, the same set of data can look very different. It's important to understand that there are some common mistakes to avoid when making graphs. In addition, advertisers have been known to intentionally make their graphs misleading to make their data match their point.  

In the image provided, this is a good example of a misleading graph.

First, notice that we know that the first bar is 10 and the second bar is 50. However, there are no labels on the horizontal or vertical axis so we don't know what the bars represent.

In addition, notice that there is no title on this graph. Since there is no title on the graph, we don't know anything about the data.

Further, look at the scale on the vertical axis. Notice that it's an uneven scale. The uneven scale makes it appear that the first bar is closer to the second bar than it actually is.

We could correct this graph by adding labels to the x and y-axis, adding a title to the graph, and making the scale on the vertical axis even.

Another way graphs can be misleading is using the wrong type to represent data. For example, a scatter plot might be better than a regular graph in some cases.

Lastly, graphs can be misleading by adding a wide range of numbers to show and increase or decrease relatively small to how it actually is.

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Olenka [21]

Answer:

a. y2×

b.y1×

c.y1×

d.y2×

e.1×

4 0
2 years ago
Agrupe os termos e fatore <br><br> xy+2x+5y+10
otez555 [7]
(y+2) (x+5) this your answer
5 0
3 years ago
How do you do these problems
avanturin [10]
\cfrac{1}{3} =   \cfrac{2}{6}  =  \cfrac{3}{9}   =  \cfrac{6}{18}

\cfrac{4}{20} = \cfrac{3}{15} =  \cfrac{12}{60}  =  \cfrac{100}{500}

7 0
3 years ago
Let f ( x , y )=5 x and let C be the segment of the parabola y = 2 x squared joining O( 0 , 0 ) and P( 1 , 2 ). a. Find a parame
taurus [48]

a. We can parameterize C by

x=t

y=2t^2

with 0\le t\le1. Then

\displaystyle\int_C5x\,\mathrm dS=\int_0^15t\sqrt{1+16t^2}\,\mathrm dt=\dfrac5{48}(17^{3/2}-1)

b. We can parameterize the opposite direction by instead setting

x=1-t

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with 0\le t\le 1. Then

\displaystyle\int_C5x\,\mathrm dS=\int_0^15(1-t)\sqrt{1+16(1-t)^2}\,\mathrm dt=-\int_1^05u\sqrt{1+16u^2}\,\mathrm dt=\int_0^15u\sqrt{1+16u^2}\,\mathrm du

which gives the same value as in part (a).

5 0
3 years ago
P = a + b + c; solve for b
Luden [163]

Answer:

b = P - a - c

Step-by-step explanation:

Step 1: Write equation

P = a + b + c

Step 2: Solve for <em>b</em>

  1. Subtract a on both sides: P - a = b + c
  2. Subtract c on both sides: P - a - c = b
  3. Rewrite: b = P - a - c
7 0
3 years ago
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