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3 years ago

What are the possible values of x if (4c-5)^2= 49?

Mathematics

2 answers:

kykrilka [37]3 years ago

7 0

Answer:

c = 3 c = -1/2

Step-by-step explanation:

(4c-5)^2= 49

Take the square root of each side

sqrt((4c-5)^2)= ±qrt(49)

4c-5 = ±7

Separate into two equations

4c-5 = 7 4c-5 = -7

Add 5 to each side

4c-5+5 = 7+5 4c-5+5 =-7+5

4c =12 4c = -2

Divide by 4

4c/4 = 12/4 4c/4 = -2/4

c = 3 c = -1/2

Setler [38]3 years ago

3 0

Answer:

c = -½, 3

Step-by-step explanation:

(4c - 5)² = 49

4c - 5 = +/- 7

4c - 5 = 7

4c = 12

c = 3

4c - 5 = -7

4c = -2

c = -½

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