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matrenka [14]
3 years ago
13

What are the possible values of x if (4c-5)^2= 49?

Mathematics
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

c = 3                              c = -1/2

Step-by-step explanation:

(4c-5)^2= 49

Take the square root of each side

sqrt((4c-5)^2)= ±qrt(49)

4c-5 = ±7

Separate into two equations

4c-5 = 7           4c-5 = -7

Add 5 to each side

4c-5+5 = 7+5          4c-5+5 =-7+5

4c =12                         4c = -2

Divide by 4

4c/4 = 12/4                     4c/4 = -2/4

c = 3                              c = -1/2

Setler [38]3 years ago
3 0

Answer:

c = -½, 3

Step-by-step explanation:

(4c - 5)² = 49

4c - 5 = +/- 7

4c - 5 = 7

4c = 12

c = 3

4c - 5 = -7

4c = -2

c = -½

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To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

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