The captain of a ship at point A and sailing toward point B observes a lighthouse at L and finds angle LAC to be 36*30'. After s
ailing 5 km to B, he observes angle LBC to be 73*. How many kilometers is position B from the lighthouse?
1 answer:
Answer:
The distance between B and lighthouse is 3.8688 km
Step-by-step explanation:
Given:
The angle made from ship to lighthouse is 36.5 degrees
and that of point B is 73 degrees.
To Find:
Distance Between Point B and Lighthouse
Solution:
<em>Consider a triangle LAB(Refer the attachment )</em>
And Point C is on the line AB as A i.e. ship is sailing to B
So C is at 5 km from A.
Now In triangle LAC,
Using Trigonometry Functions as ,
tan(36.5)=LC/AC
LC=tan(36.5)*AC
=0.7399*5
=3.6998 km
Now In triangle LBC,
As,
Sin(73)=LC/LB
LB=LC/(Sin(73))
=3.6998/0.9563
=3.8688 km
LB=3.8688 km
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Answer:
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Step-by-step explanation:
We are given;
n = 27 bags
Sample mean;X = 402 gram
Population mean;μ = 404 gram
Variance = 676
We know that, standard deviation(σ) = √variance
Thus;
σ = √676
σ = 26
The hypotheses are;
Null hypothesis; H0: μ = 404
Alternative hypothesis; HA: μ < 404
Let's find the z-score from the formula;
z = (X - μ)/(√σ/n)
z = (402 - 404)/√(26/27)
z = -2.04
From the z-distribution table attached, we have a p-value of 0.02068
This is less than the significance value of 0.01 and thus we will reject the null hypothesis and conclude that there is no sufficient evidence to support the claim that the bags are underfilled
Answer:
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Step-by-step explanation:
Given that,
Justin walks 200 feet to the east, then turns and walks 120 feet due south.
We need to find the total distance walked by Justin. Let the distance be d.
We can use the Pythagoras theorem to find it such that,
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