Answer:
The sequence is:
10, 30, 50, 70, 90.....................
Step-by-step explanation:
We have,
First term (a) = 10
Common difference (d) = ?
Sum of first 5 terms (
) = 250
or, ![\frac{n}{2} [{2a+(n-1)d}] = 250](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%20%5B%7B2a%2B%28n-1%29d%7D%5D%20%3D%20250)
or, ![\frac{5}{2} [2*10 + 4d]=250](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%5B2%2A10%20%2B%204d%5D%3D250)
or, ![\frac{5}{2} * 4[5+d]=250](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20%2A%204%5B5%2Bd%5D%3D250)
or, 10(5 + d) =250
or, 5 + d = 25
∴ d = 20
Now,
2nd term = a + d = 10 + 20 = 30
3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50
4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70
5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90
Answer:
-10
Step-by-step explanation:
-4 + -3 = -7
-7 + -2 = -9
-9 + -1 = -10
Answer:
1065
Step-by-step explanation:
57-42×-3-21
Step-by-step explanation:
well, the first solution that comes to my mind is :
8/4 + 5/1 = 7/1
2 + 5 = 7
the reason : the only numerator I can "cut" into integer pieces is 8.
5 and 7 are prime numbers.
so, it tried to keep 5 and 7 whole, and then add a part of 8 to make this equation true. and that worked right away.
Its the first one: Letter A
