<span>96-ounce container of orange juice cost $4.80
</span><span>128-ounce ................................................?
4.80 x 128 / 96 = $6.40
answer
</span>$6.40 - <span>128-ounce container</span>
Putting this as an arithmetic sequence gives:

The sum of the series = 16 x 7 x 7 = 784 m^3 = 784 000 L
The sum of an arithmetic series can be written as:
![S_n=n/2 [2a+(n-1)d] = 784 000 \\n/2[2(150)+(n-1)200] = 784 000 \\n[300+200(n-1)=1 568 000 \\300n+200n^2-200n = 1 568 000 \\200n^2+100n- 1 568 000 = 0 \\2n^2 +n- 15680 = 0 \\n= 88.2...,-88.7](https://tex.z-dn.net/?f=S_n%3Dn%2F2%20%5B2a%2B%28n-1%29d%5D%20%3D%20784%20000%0A%5C%5Cn%2F2%5B2%28150%29%2B%28n-1%29200%5D%20%3D%20784%20000%0A%5C%5Cn%5B300%2B200%28n-1%29%3D1%20568%20000%0A%5C%5C300n%2B200n%5E2-200n%20%3D%201%20568%20000%0A%5C%5C200n%5E2%2B100n-%201%20568%20000%20%3D%200%0A%5C%5C2n%5E2%20%2Bn-%2015680%20%3D%200%0A%0A%5C%5Cn%3D%2088.2...%2C-88.7)
n has to be positive, so we get
n =
<u>88.2 hours (3 s.f.)</u>
Answer:
16.1157
Step-by-step explanation:
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the required lengths are not given.
I will use the following data set to answer the question.

First, is to determine the range of the dataset



Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval




<em>So, we use 4 classes</em>
Plot the frequency distribution table as follows:

<em>See attachment for histogram</em>