Hey there!
6 divided by 5 = 1.2
Hope this helps!
Have a great day! (:
Answer:
Step-by-step explanation:
<u>Given</u>:
If you are dealt 4 cards from a shuffled deck of 52 cards.
We need to determine the probability of getting two queens and two kings.
<u>Probability of getting two queens and two kings:</u>
The number of ways of getting two queens is ![4C_2](https://tex.z-dn.net/?f=4C_2)
The number of ways of getting two kings is ![4C_2](https://tex.z-dn.net/?f=4C_2)
Total number of cases is ![52C_4](https://tex.z-dn.net/?f=52C_4)
The probability of getting two queens and two kings is given by
![\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}](https://tex.z-dn.net/?f=%5Ctext%20%7Bprobability%7D%3D%5Cfrac%7B%5Ctext%20%7BNo.of%20fanourable%20cases%7D%7D%7B%5Ctext%20%7BTotal%20no.of%20cases%7D%7D)
Substituting the values, we get;
![probability=\frac{4C_2 \cdot 4C_2}{52C_4}](https://tex.z-dn.net/?f=probability%3D%5Cfrac%7B4C_2%20%5Ccdot%204C_2%7D%7B52C_4%7D)
Simplifying, we get;
![probability=\frac{6 (6)}{270725}](https://tex.z-dn.net/?f=probability%3D%5Cfrac%7B6%20%286%29%7D%7B270725%7D)
![probability=\frac{36}{270725}](https://tex.z-dn.net/?f=probability%3D%5Cfrac%7B36%7D%7B270725%7D)
![probability=0.000133](https://tex.z-dn.net/?f=probability%3D0.000133)
Thus, the probability of getting two queens and two kings is 0.000133
Answer:
u need 2 equation to solve
Step-by-step explanation:
I believe it’s C. Have a good day.