Sally eats 3/4 of an Apple in 3/5 of a minute. How much time will it take her to eat a full apple

I need help ASAP whit this question

sweet [91]

Answer:

B. 7

Step-by-step explanation:

The original box must be 1 by 1 by 1.

So then the new box would be 2 by 2 by 2.

2×2×2=8

8-1=7

I hope this helps!

pls ❤ and mark brainliest pls!

7 0

2 years ago

A jar contains 10 marbles marked with the numbers 1 through 10. You pick a marble at random. What is the probability of not pick

mr_godi [17]

Answer:

9/10

Step-by-step explanation:

Since there is only one marble per number and there is only one marble for the number 8 you would take just subtract 10-1 which would give you 9.

5 0

2 years ago

Can you guys help me

natita [175]

Answer:

would be A

Step-by-step explanation:

because bisecting means both sides equal the same. so 4x-12 times two is 8x-24. Hope this helps

4 0

3 years ago

Read 2 more answers

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$