Answer:
0.0002
Step-by-step explanation:
hope this helps
The maximum data rate on any line with zero bandwidth is zero.
The expression for (t) \Join (t+2) - (t+1) \Join (t+1) is (
+ t - 2 ) (
+ t - 6 ).
The given operation is \Join such that x Join y = (x+2)(y-3).
We are to apply the \Join operation in the given expression.
t \join (t+2) - (t+1) \Join (t+1) and find its final expression.
Using this operation: x Join y = (x+2)(y-3).
Let's find,
t \join (t+2)
Here,
x = t and y = t + 2
= ( t+2 ) ( t+2 - 3 )
= ( t + 2 ) ( t - 1 )
(t+1) \Join (t+1)
Here,
x = t + 1 and y = t + 1
= ( t + 1 + 2 ) ( t + 1 - 3 )
= ( t + 3 ) ( t - 2 )
t \join (t+2) - (t+1) \Join (t+1)
= ( t + 2 ) ( t - 1 ) - ( t + 3 ) ( t - 2 )
= (
- t + 2t - 2 ) (
- 2t + 3t - 6 )
= (
+ t - 2 ) (
+ t - 6 )
Thus the expression for (t) \Join (t+2) - (t+1) \Join (t+1) is:
(
+ t - 2 ) (
+ t - 6 )
Learn more about mathematical operation here:
brainly.com/question/27915566
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Answer:
Parts of oil in 42 cups of marinade = 21 cups
Parts of soy sauce in 42 cups of marinade = 14 cups
Parts of orange juice in 42 cups of marinade = 7 cups
Step-by-step explanation:
Given that:
Parts of oil = 3
Parts of soy sauce = 2
Part of orange juice = 1
Total cups of marinade = 42
To find:
How much of each ingredient should be there ?
Solution:
This problem can be solved by taking the ratio of ingredients into account.
The ratio is:
Oil : Soy Sauce : Orange Juice = 3 : 2 : 1
So, we can let the parts of oil = 
Parts of soy sauce = 
Parts of orange juice = 
As per the question statement:

So, parts of oil in 42 cups of marinade = 3
7 = 21 cups
Parts of soy sauce in 42 cups of marinade = 2
7 = 14 cups
Parts of orange juice in 42 cups of marinade = 7 cups
Answer: y=-2x-4 (C)
Step-by-step explanation: Its correct i swear