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Ksivusya [100]
2 years ago
7

Jovie is maintaining a camp fire. She has kept the fire steadily burning for 10hours with 15 logs. She wants to know how many ho

urs (h) she could have kept the fire going with 9 logs. She assumes all logs are the same.
Please help!
Mathematics
2 answers:
vitfil [10]2 years ago
5 0

You are given following <u>data</u>:

15 logs - 10 hours,

9 logs - x hours.

Use <u>proportion</u> to determine unknown <u>value</u> of x:

\dfrac{15}{9}=\dfrac{10}{x}.

Then

15\cdot x=9\cdot 10,\\ \\x=\dfrac{90}{15}=6\ hours.

Answer: 6 hours

ozzi2 years ago
3 0

Answer:6


Step-by-step explanation:


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7 0
2 years ago
According to a study done by a university​ student, the probability a randomly selected individual will not cover his or her mou
Sergio [31]

Using the binomial distribution, it is found that:

a) There is a 0.1618 = 16.18% probability that among 18 randomly observed individuals exactly 6 do not cover their mouth when​ sneezing.

b) There is a 0.104 = 10.4% probability that among 18 randomly observed individuals fewer than 3 do not cover their mouth when​ sneezing.

c) 9 is more than 2.5 standard deviations below the mean, hence it would not be surprising if fewer than half covered their mouth when​ sneezing.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The values of the parameters are given as follows:

n = 18, p = 0.267.

Item a:

The probability is P(X = 6), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{18,6}.(0.267)^{6}.(0.733)^{12} = 0.1618

There is a 0.1618 = 16.18% probability that among 18 randomly observed individuals exactly 6 do not cover their mouth when​ sneezing.

Item b:

The probability is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.267)^{0}.(0.733)^{18} = 0.0037

P(X = 1) = C_{18,1}.(0.267)^{1}.(0.733)^{17} = 0.0245

P(X = 2) = C_{18,2}.(0.267)^{2}.(0.733)^{16} = 0.0758

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0037 + 0.0245 + 0.0758 = 0.104.

There is a 0.104 = 10.4% probability that among 18 randomly observed individuals fewer than 3 do not cover their mouth when​ sneezing.

item c:

We have to look at the mean and the standard deviation, given, respectively, by:

  • E(X) = np = 18 x 0.267 = 4.81.
  • \sqrt{V(X)} = \sqrt{18(0.267)(0.733)} = 1.88

9 is more than 2.5 standard deviations below the mean, hence it would not be surprising if fewer than half covered their mouth when​ sneezing.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0
2 years ago
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