Two boats leave the same port, heading in opposite directions. One boat travels at 10 miles per hour and the other boat travels
1 answer:
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1. Domain.
We have
in the denominator, so:
![x^2-2x-3\neq0\\\\(x^2-2x+1)-4\neq0\\\\(x-1)^2-4\neq0\\\\(x-1)^2-2^2\neq0\qquad\qquad[\text{use }a^2-b^2=(a-b)(a+b)]\\\\(x-1-2)(x-1+2)\neq0\\\\ (x-3)(x+1)\neq0\\\\\boxed{x\neq3\qquad\wedge\qquad x\neq-1}](https://tex.z-dn.net/?f=x%5E2-2x-3%5Cneq0%5C%5C%5C%5C%28x%5E2-2x%2B1%29-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-4%5Cneq0%5C%5C%5C%5C%28x-1%29%5E2-2%5E2%5Cneq0%5Cqquad%5Cqquad%5B%5Ctext%7Buse%20%7Da%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D%5C%5C%5C%5C%28x-1-2%29%28x-1%2B2%29%5Cneq0%5C%5C%5C%5C%0A%28x-3%29%28x%2B1%29%5Cneq0%5C%5C%5C%5C%5Cboxed%7Bx%5Cneq3%5Cqquad%5Cwedge%5Cqquad%20x%5Cneq-1%7D)
So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.
2. Asymptotes:
We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
We have
So there is a hole or an asymptote at x = 3 and x = -1 and we know, that answer B) is wrong.
2. Asymptotes:
We have only one asymptote at x = -1 (and hole at x = 3), thus the correct answer is A)
The dot plot of the data recorded by Tricia about number of pets owned by each of her classmates looks like scattered and some points are in one line.
Given number of pets owned by each of her classmates are: 0, 3, 2, 4, 1, 0, 0, 3, 2, 1, 2, 1, 1, 3, 4, 2, 0, 0, 1, 1, 1, 0, 3.
We have to create dot plot of the data given in the question.
Firstly we have to give a code to each value which represents friend of Tricia.
A dot plot is a statistical chart which have points but they are presented in dot form. Each dot shows a value .There are two common, yet different versions of the dot chart.
After giving codes the table will look like:
Friend Number of pets
1 0
2 3
3 2
4 4
5 1
6 0
7 0
8 3
9 2
10 1
11 2
12 1
13 1
14 3
15 4
16 2
17 0
18 0
19 1
20 1
21 1
22 0
23 3
Learn more about dot plot at brainly.com/question/15853311
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