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saul85 [17]
3 years ago
9

Find X in the triangle. Round answer to the nearest TENTH of a degree (GIVING BRAINLEST TO BEST ANSWER :D ) ​

Mathematics
2 answers:
Sergio [31]3 years ago
7 0

Answer:

x = 59,53445508

Tan(x) = 34/20

Step-by-step explanation:

Lostsunrise [7]3 years ago
5 0

Answer:

30÷20 degree x=n

Step-by-step explanation:

Mark me as brainliest

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A box of breakfast tacos coat $12 and a contains 8 tacos how much dose each taco coast
Rom4ik [11]

Answer:

$1.50

Step-by-step explanation:

12/8 = 1.50

3 0
3 years ago
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Anlatarak cozmicekseniz cevaplamayin:) ​
expeople1 [14]
Wish I could help! But maybe one day I can and hopefully there’s someone on here that and assist you!
8 0
3 years ago
A parking garage allows users to park the first hour free and then charges $2.50 for each additional hour or fraction of an hour
Snowcat [4.5K]

The first hour is free, and the rest charges is $2.50


Let x be the time.

Let y be the total


Your equation will look like


When x < 2, y = 0

When x > 1, y = $2.50(x)


So:


1 < x < ∞ for hours, then equation will look like:

y = total amount

$2.50 is cost (remember that the first hour is for free, and so you subtract $2.50 from the total.


$2.50x - $2.50 = y should be your equation.


hope this helps

6 0
3 years ago
Read 2 more answers
Write the expanded form of the expression<br> y(0.25 +6)
Murrr4er [49]

Answer:

free points for a easy question.   You do 0.25+6 in expanded form

Step-by-step explanation:

8 0
3 years ago
In studies for a​ medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.
timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

p = 0.03

q = 1 - 0.03 = 0.97

The mean is

\mu  = np

\mu = 643 \times 0.03 = 19.29

The standard deviation is

\sigma =  \sqrt{npq}

\sigma =  \sqrt{643 \times 0.03 \times 0.97}

\sigma =4.33

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \:  \frac{24.5 - 19.29}{4.33} ) \\  = P( 0.97\: < \: z \: < \:  1.20) \\  = 0.051

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

P(X \: < \: 24.5) = P(z \: < \:  \frac{24.5 - 19.29}{4.33} )  \\ =   P(z \: < \: 1.20)  \\  = 0.8849

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

P(X \: > \: 10.5) = P(z \: > \:  \frac{10.5 - 19.29}{4.33} )  \\ = P(z \: > \:  - 2.03)

= 0.9788

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

P(23.5  \:  <  \: X \:  <  \: 28.5) = P( \frac{23.5 - 19.29}{4.33}   \:  <  \: z \:  <  \:  \frac{28.5 - 19.29}{4.33} ) \\  = P( 0.97\:  <  \: z \:  <  \: 2.13) \\  = 0.1494

3 0
3 years ago
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