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cluponka [151]
2 years ago
14

Please help !!!! find the tangent of angle (-)

Mathematics
1 answer:
Troyanec [42]2 years ago
8 0
15/8. Tangent = opposite / adjacent line
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P(t+1)=-2<br>how would solve for t
Phantasy [73]
P(t+1) = -2

divide by P
Subtract 1

T equals negative 2 over P minus 1

T = -2/P -1
8 0
3 years ago
El Club de Matemáticas está horneando pasteles para una venta de
SVETLANKA909090 [29]

Answer:

56

Step-by-step explanation:

El problema se puede transcribir en esta ecuación:

2x + x = 168

siendo x las nectarinas

sumas los términos de x:

3x=168

despejas x:

x = 168 ÷ 3

x = 56

5 0
2 years ago
Two friends are training for the marathon. Shaneese runs 100 miles per week, give or take 5 miles. Denasia runs 20 miles per wee
Svetach [21]

Answer:

give or take 5 miles.

Step-by-step explanation:

im not shor but that is true about the both of them

7 0
2 years ago
Read 2 more answers
Each side of the smaller square in the figure below is n inches long, and each side of the larger square is p inches longer than
lana66690 [7]

Answer:

2np + p²

Step-by-step explanation:

The general formula for the area of a square is A = s², where s = the length of one side of the square.  In the case of the smaller square the area would be: n x n = n².  Since the side of the larger square is 'p' inches longer, the length of one side is 'n + p'.  To find the area of the larger square, we have to take the length x length or (n +p)².

Using FOIL (forward, outside, inside, last):

(n + p)(n+p) = n² + 2np + p²

Since the area of the first triangle is n², we can subtract this amount from the area of the larger square to find out how many square inches greater the larger square area is.

n² + 2np + p² - n² = 2np + p²


8 0
3 years ago
K=mv^2/2 solve for v
matrenka [14]

Answer: v=\sqrt[]{\frac{2K}{m} }

Step-by-step explanation:

K=\frac{mv^2}{2}

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

2*K=\frac{mv^2}{2}*2

2K=mv^2

Divide by m to isolate v^2.

\frac{2K}{m}=\frac{mv^2}{m}

\frac{2K}{m} =v^2

To eliminate the square and isolate v, extract the square root.

\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}

\sqrt[]{\frac{2K}{m} }=v

let's rewrite it in a way that v is in the left side.

v=\sqrt[]{\frac{2K}{m} }

4 0
2 years ago
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