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labwork [276]
2 years ago
14

Find the product. -2x(x2 - 3) -2 x3 - 6 x -2 x2 6 x 6 x3 -2 x3 6 x.

Mathematics
1 answer:
belka [17]2 years ago
6 0

Product of two polynomials can be done by distribution of multiplication over addition. The product of  -2x(x^2 - 3) is -2x^3 + 6x

<h3>What is distributive property of multiplication over addition?</h3>

Suppose a, b and c are three numbers. Then we have:

a(b + c) = a\times b + a\times c

(a(b+c) means a multiplied to (b+c). The sign of multiplication is usually hidden when using symbols and both quantities which are in multiplication are written together without space)

The product result of the given expression is

-2x(x^2 - 3) = -2x^{1 + 2} + 6x = -2x^3 + 6x

It is because when bases are same and there is multiplication, then powers add up, so we have: a^b \times a^c = a^{b+c}

Thus,

The product of  -2x(x^2 - 3) is -2x^3 + 6x

Learn more about product of polynomials here:

brainly.com/question/9106484

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This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


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2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


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