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2 years ago

8

A recipe calls for 2/3 cup of chopped walnuts. You chop 4 walnuts and get 1/4 of the amount you need. How much more of a cup of

chopped walnuts do you need?

1 answer:

bulgar [2K]2 years ago

5 0

Answer: 1.66 cups neededed

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What are the real roots of the given rational equation? (x + 3)

ankoles [38]

<span>(x – 1) = 1
</span>Hope this helps ((:

4 0

3 years ago

Enrique left the study group traveling 20 mph. Then, 2 hours later, Tevin left traveling the same direction at 28 mph. How long

nadya68 [22]

Answer:

After 7 hours Tevin will catch Enrique

Step-by-step explanation:

We have given speed of Enrique is 20 mph

Tevin left traveling after 2 hours of Enrique

Speed of Tevin is 28 mph

When Tevin catches Enrique will cover same distance

Let Enrique is traveling for t hours

Then Tevin will travel for t-2 hours

We know that distance = speed × time

So $20\times t=28\times (t-2)$

$20t=28t-56$

$8t=56$

t = 7 hours

So after 7 hours Tevin will catch Enrique

4 0

4 years ago

I really dont get this question

Gre4nikov [31]

Answer:

10,000

Step-by-step explanation:

Example:

.01 × 10,000 = 100

4 0

3 years ago

Read 2 more answers

I need help on two questions!

Inessa05 [86]

1) Answer: $\frac{x^{2}}{100} +\frac{y^{2}}{4} = 1$

<u>Explanation:</u>

The equation of an ellipse is: $\frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1$ ; where (h, k) is the center, "a" is the x-radius, and "b" is the y-radius.

Center Radius

x-axis: (10 + -10)/2 = 0 10 - 0 = 10

h = 0 a = 10

y-axis: (2 + -2)/2 = 0 2 - 0 = 2

k = 0 b = 2

Now, input the values into the equation:

$\frac{(x-0)^{2}}{10^{2}} +\frac{(y-0)^{2}}{2^{2}} = 1$

$\frac{x^{2}}{100} +\frac{y^{2}}{4} = 1$

************************************************************************

2) Answer: $\frac{x^{2}}{1} +\frac{(y+2)^{2}}{4} = 1$

<u>Explanation:</u>

Vertices are: (0, 1) and (0, -5) ------> x-values are the same, y = 1, -5

Covertices are: (-1, -2) and (1, -2) ----> y-values are the same, x = -1, 1

Center Radius

x-axis: (-1 + 1)/2 = 0 1 - 0 = 1

h = 0 a = 1

y-axis: (1 + -5)/2 = -2 1 - (-2) = 3

k = -2 b = 3

Now, input the values into the equation:

$\frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1$

$\frac{(x-0)^{2}}{1^{2}} +\frac{(y-(-2))^{2}}{3^{2}} = 1$

$\frac{x^{2}}{1} +\frac{(y+2)^{2}}{9} = 1$

3 0

4 years ago

Plz help<br><br><br> I call this evil....

Umnica [9.8K]

9≤c + 1
In this question we will first solve for the variable. ( i.e. c )
so,
subtracting both sides by 1 we get
8 ≤ c
or
c ≥ 8

And we know that if we have ≤ or ≥ we have a HARD dot on the point.
So, our graph will start from point 8 goes to the right.

hope this helped.. :)

6 0

3 years ago