(a) 151 degrees (supplementary angles add to 180’)
(b) 48 degrees (complementary angles add to 90’)
Given that the height of the ball has been modeled by h=120t-16t^2, the reasonable range will be found as follows:
maximum height is attained when h'(t)=0
given h=120t-16t^2
h'(t)=120-32t=0
thus solving for t, we get:
t=3.75 sec
thus the maximum time attained will be:
120(3.75)-16(3.75)^2=225 ft
Therefore the reasonable range will be [0≤h(t)≤225]
Answer:
24
Step-by-step explanation:
26^2-10^2 = 576
sqrt576 = 24
Answer:
y = (x - 2)² + 9
Step-by-step explanation:
To obtain the equation in vertex form use the method of completing the square.
Add/ subtract ( half the coefficient of the x- term)² to x² - 4x
y = x² + 2(- 2)x + 4 - 4 + 13
= (x - 2)² + 9 ← in vertex form
Answer :Could you take a better photo? I dont quite understand what needs to be found there
Step-by-step explanation: