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slavikrds [6]
3 years ago
9

How to do this , PLEASE HELP

Mathematics
1 answer:
Oksana_A [137]3 years ago
7 0
\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  x^{123}  x_{123}  \sqrt[n]{x}  \sqrt[n]{x}  x_{123}  \lim_{n \to \infty} a_n  \int\limits^a_b {x} \, dx =1
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Manesh is putting new tile on a kitchen counter. Each sheet of tile will cover 1.5 \text { ft}^21.5 ft 2 1, point, 5, start text
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12

Step-by-step explanation:

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3 years ago
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The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va
Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore

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3 years ago
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mixer [17]

Step-by-step explanation:

-3-4 -32x=3×8x

-3-4-32x=24x

-6=32x+24x

-6=56x

:. x=-28/3

3 0
3 years ago
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