9514 1404 393
Answer:
- 85°
- 60°
Step-by-step explanation:
1. Angle JKL is half the measure of the intercepted arc JK.
(1/2)JK = 1/2(360° -190°) = (1/2)(170°) = 85°
angle JKL is 85°
__
2. The angle between tangents is the supplement of the intercepted arc.
angle JKL = 180° -(360° -240°)
angle JKL = 60°
Answer:
65
Step-by-step explanation:
They are vertical angles; so angles are congruent
*<em>Vertical angles are always congruent*</em>
<em>Congruent means equal or same.</em>
1) Since they are congruent, you form an equation.
<h2>
145 = 2x + 15</h2>
2) Solve by subtracting 15 from both sides.
<h2>
145 = 2x + 15</h2><h2>
- 15 -15</h2><h2>
----------------------</h2><h2>
130 = 2x</h2>
3) Solve by dividing 2 from both sides
<h2>
130/2 = 2x/2</h2>
4) Simplify
x = 65
18 x 3 + 12 - 1 x 34 + 13 - 2 x 56 = 67
<=Work=>
18 x 3 = 54
1 x 34 = 34
2 x 56 = 112
(54) + 12 - (34) + 13 - (112)
66 - 34 + 13 - 112
32 + 13 - 112
45 - 112
= 67
Answer:
b
Step-by-step explanation:
The equation:
3
x
2
−
5
x
−
12
=
0
is in the form:
a
x
2
+
b
x
+
c
=
0
with
a
=
3
,
b
=
−
5
,
c
=
−
12
The roots are given by the quadratic formula:
x
=
−
b
±
√
b
2
−
4
a
c
2
a
x
=
5
±
√
(
−
5
)
2
−
4
(
3
)
(
−
12
)
2
(
3
)
x
=
5
±
√
25
+
144
6
x
=
5
±
√
169
6
x
=
5
±
13
6
That is:
x
=
5
+
13
6
=
18
6
=
3
or
x
=
5
−
13
6
=
−
8
6
=
−
4
3
Answer:
Step-by-step explanation:
The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by
We first compute the n-th derivative of 
, note that
Now, if we compute the n-th derivative at 0 we get
and so the Maclaurin series for f(x)=ln(1+2x) is given by
