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zhuklara [117]
3 years ago
10

Helppppp meeee pleassseee

Mathematics
1 answer:
algol133 years ago
7 0

Answer:

Defiantly B.

Happy that Help!

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Are these arithmetic sequences:
VladimirAG [237]

Answer:

1. No

2. Yes

3. Yes

4. Yes

Step-by-step explanation:

In 1. the difference between each term is not constant.(it goes up by, 2, 4, 6)

2. The terms increase by the same amount(it all goes up by 3)

3. The terms decrease by the same amount(it all goes down by 5)

4. The terms increase by the same amount(it all goes up by 6)

8 0
3 years ago
a parent died and left an estate to four children. One inherited 1/2 the second inherited 1/8 and the third inherited 1/4. how m
djyliett [7]
1/2+1/8+1/4=7/8    
4/8+1/8+2/8=7/8

1-7/8 = 3/8
the fourth on inherited 3/8 of the estate.
7 0
3 years ago
Are all irrational numbers real numbers. If so , why
Elena L [17]
Yes, all numbers are real numbers because a number is a number, and nothing can change that. I hope this helps you!











5 0
3 years ago
Admission to a car show costs $5 for each ticket. After selling only 20 tickets, they decided to lower the price to $3 each. If
Naddik [55]
First you would multiple 5 × 20 which equals $100 then you would subtract $217 by $100 and you would get 39 tickets and then you would add your twenties tickets and your 39 tickets together to get your answer which is 59 tickets.
5 0
3 years ago
Read 2 more answers
A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0
2 years ago
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