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TEA [102]
2 years ago
10

HELP ME PLEASE I REALLY NEED THE ANSWER! THIS IS REALLY HARD! (THE ANSWER IS NOT A I HAVE TRIED IT AND IT WAS WRONG AND ITS AN A

NSWER ONCE QUESTION SO I HAVE TO COMMENT IT)

Mathematics
2 answers:
Kobotan [32]2 years ago
5 0

Answer:

The answer is E

Step-by-step explanation:

hope it helps

ch4aika [34]2 years ago
5 0

Answer:

Option E

(-1, 0, 1, 2, 3, 4, 5, 6)

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • -2 < n ≤ 6

So,

n is less than (-2) but greater than or equal to 6

Now, the possible value of n

-1, 0, 1, 2, 3, 4, 5, 6

Thus, (-1, 0, 1, 2, 3, 4, 5, 6) are the possible values of n

 

<u>-TheUnknownScientist 72</u>

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A newspaper reporter says that a company made 700,000 profit last year it says this was 12% more then the year before . Work out
Dmitriy789 [7]

Answer:

625000

Step-by-step explanation:

x+12%= 700000

x*1.12=700000

x=700000/1.12

x=625000

4 0
3 years ago
Which expression is equivalent??? help!
dexar [7]

Answer:

The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

Step-by-step explanation:

Given:

\sqrt[3]{256x^{10}y^{7} }

Solution:

We will see first what is Cube rooting.

\sqrt[3]{x^{3}} = x

Law of Indices

(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}

Now, applying above property we get

\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y   )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})

∴ The equivalent expression for the given expression \sqrt[3]{256x^{10}y^{7} } is

4x^{3} y^{2}(\sqrt[3]{4xy} )

5 0
3 years ago
How do i do this ?i need help on finding the answer . To all three questions
Igoryamba

Answer:

area of larger circle : 9π = 28.27

area of smaller circle: 4π = 12.57

area of shaded region: 15.71

Step-by-step explanation:

area of a circle = πr^2

I think these are right i dont know tho

8 0
3 years ago
I will mark brainiest please help me im stuck on this questionnnn
Bess [88]
I guess It would be B
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3 years ago
A florist has an order to make flower bouquets. The order calls for the use of 45 roses and 63 carnations. Each bouquet made wil
Solnce55 [7]
Highest common factor of 63 and 45 is 9.
Therefore there can be 9 bouquets each with 5 roses and 7 carnations
6 0
3 years ago
Read 2 more answers
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