<span>During interphase, the DNA in the nucleus of the cell is thin and threadlike and called chromatin.
></span>Chromatin<span> is a complex of DNA and proteins that creates chromosomes within the nucleus of eukaryotic cells.
></span>Chromatin<span> is a mass of genetic material comprised of DNA and proteins which condenses to form chromosomes.</span>
A Negative stain such as India ink or Congo red-Look for the presence of a capsule.
This stain method is usually used to stain the area around the microorganism.
B The Gram stain-Divide bacteria into two groups based on cell wall structure (thick vs. thin).
This is type of differential staining used to distinguish organisms based on their staining properties. Gram + and Gram- bacteria stain different because of different cell wall structure.
C The Ziehl-Neelsen Acid-fast stain- Identify bacteria with waxy cell walls such as: Mycobacterium tuberculosis (the cause of TB).
This is also differential staining method which uses heat and phenol to derive dye into the cells with lipid-rich walls.
D Simple stain with a basic dye-Stain microbes a bright color to make it easier to see them in bright field microscopy.
One dye is used in simple staining in order to determinate the size, shape and arrangement of the cells.
E The Schaeffer-Fulton Endospore stain-Identify Bacillus or Clostridium species, such as the causative agents of anthrax, botulism, tetanus and gangrene.
This is a special type of staining only used for the bacteria that can form endospores. Bacteria are first treated with heat and then with malachite green, which is very strong stain that can penetrate endospores.
I’m pretty sure it’s water, oxygen, and food. beacuse food provided both nutrients and an energy source.
<span>In Drosophila + indicates wild-type allele for any gene, m is mahogany and e is ebony.
Female parents are m+/m+ and males are +e/+e.
F1 are m+/+e, all wild type. F1 females are crossed with me/me males - the test cross.
Offspring will be : non recombinant m+/me, mahogany wild type or +e/me wild type ebony. OR
recombinant me/me mahogany ebony or ++/++ wild type.
As the two genes are 25 map units apart, the percentage of recombinants will be 25% and therefore percentage parental types will be 75%.
75% 1000 is 750. There are two parental types, so you would expect 375 of each. Therefore, you would expect 375 m+/me and 375 +e/me.
25% of 1000 is 250 split between two recombinants =125 of each. Therefore you would expect 135 me/me and 125 ++/++</span>
