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otez555 [7]
3 years ago
14

2/21 × -3/13 +-7/9 - 2/21 × 10/13​

Mathematics
2 answers:
grin007 [14]3 years ago
7 0

Answer:

\frac{-55}{63} is the answer for the question.

Step-by-step explanation:

All you have to do is just simplify the expression And you'll get your answer as \frac{-55}{63}

Hope this helped you !

Viefleur [7K]3 years ago
5 0

Answer:

\frac{-55}{63}

Step-by-step explanation:

=\frac{2}{21}(\frac{-3}{13})-\frac{7}{9}-\frac{2}{21}(\frac{10}{13})

=\frac{-2}{91}-\frac{7}{9}-\frac{2}{21}(\frac{10}{13})

=\frac{-2}{91} +\frac{7}{9} -\frac{2}{21} (\frac{10}{13})

=\frac{-655}{819}-\frac{2}{21} (\frac{10}{13} )

=\frac{-655}{819}-\frac{20}{273}

=\frac{-55}{63}

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Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
Mice21 [21]

Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM ,

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1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

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So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

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\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

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