All categories

3 years ago

2/21 × -3/13 +-7/9 - 2/21 × 10/13

Mathematics

2 answers:

grin007 [14]3 years ago

7 0

Answer:

$\frac{-55}{63}$ is the answer for the question.

Step-by-step explanation:

All you have to do is just simplify the expression And you'll get your answer as $\frac{-55}{63}$

Hope this helped you !

Viefleur [7K]3 years ago

5 0

Answer:

$\frac{-55}{63}$

Step-by-step explanation:

$=\frac{2}{21}(\frac{-3}{13})-\frac{7}{9}-\frac{2}{21}(\frac{10}{13})$

$=\frac{-2}{91}-\frac{7}{9}-\frac{2}{21}(\frac{10}{13})$

$=\frac{-2}{91} +\frac{7}{9} -\frac{2}{21} (\frac{10}{13})$

$=\frac{-655}{819}-\frac{2}{21} (\frac{10}{13} )$

$=\frac{-655}{819}-\frac{20}{273}$

$=\frac{-55}{63}$

You might be interested in

Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce

pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0

3 years ago

A worker earns $100 every 8 hours. At this rate, how much will the worker earn in 36 hours?

patriot [66]

Answer:

The answer is $350

Step-by-step explanation:

00 = 8 hours

28/8 = 3.5

3.5(100) = 350

The worker would earn $350 in 28 hours

5 0

4 years ago

Read 2 more answers

What’s the probability of getting each card out of a deck?

VMariaS [17]

Answer:

a. 1/13

b. 1/52

c. 2/13

d. 1/2

e. 15/26

f. 17/52

g. 1/2

Step-by-step explanation:

a. In a deck of cards, there are 4 suits and each of them has a 7. Therefore, the probability of drawing a 7 is:

P(7) = 4/52 = 1/13

b. There is only one 6 of clubs, therefore, the probability of drawing a 6 of clubs is:

P(6 of clubs) = 1/52

c. There 4 fives (one for each suit) and 4 queens in a deck of cards. Therefore, the probability of drawing a five or a queen is:

P(5 or Q) = P(5) + P(Q)

= 4/52 + 4/52

= 1/13 + 1/13

P(5 or Q) = 2/13

d. There are 2 suits that are black. Each suit has 13 cards. Therefore, there are 26 black cards. The probability of drawing a black card is:

P(B) = 26/52 = 1/2

e. There are 2 suits that are red. Each suit has 13 cards. Therefore, there are 26 red cards. There are 4 jacks. Therefore:

P(R or J) = P(R) + P(J)

= 26/52 + 4/52

= 30/52

P(R or J) = 15/26

f. There are 13 cards in clubs suit and there are 4 aces, therefore:

P(C or A) = P(C) + P(A)

= 13/52 + 4/52

P(C or A) = 17/52

g. There are 13 cards in the diamonds suit and there are 13 in the spades suit, therefore:

P(D or S) = P(D) + P(S)

= 13/52 + 13/52

= 26/52

P(D or S) = 1/2

6 0

3 years ago

A guy wire supports an antenna tower, as shown at the right. The bottom of the wire is secured in the ground 30 feet from the ba

babunello [35]

Answer:

The wire is approximately 42feet long

Step-by-step explanation:

We can mentally sketch out the shape that is formed between the guy wire and the antenna tower. This is simply a right-angled triangle with the opposite side being the height of the antenna (30 feet). The adjacent side is the distance on the ground between the point where the wire was fastened and the base of the antenna.

The hypotenuse side is the length of the wire we are looking for.

Parameters are given as:

Opposite : 30ft

Adjacent: 30ft

Hypotenuse: x feet

The hypotenuse = $\sqrt{opp^2 + adj^2}$