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Firlakuza [10]
3 years ago
11

Question 3 Written response Help please

Mathematics
2 answers:
Readme [11.4K]3 years ago
4 0

Answer:

Brad

Step-by-step explanation:

(5x + 2)/x² = 5/x + 2/x²

= 5x^-1 + 2x^-2

Which is not a polynomial

natali 33 [55]3 years ago
3 0

Answer:

Brad

Step-by-step explanation:

(5x + 2)/x² = 5/x + 2/x²

= 5x^-1 + 2x^-2

Which is not a polynomial

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If randy earns $12.74 per hour, what is his overtime rate? How much should randy make if he works 45 1/2 hours during 1 week?
elena-14-01-66 [18.8K]

Answer:

$19.24 is the overtime rate $579.67 one week

Step-by-step explanation:

So $13.00 its $19.50 so I subtracted $12.74 to $13.00 got 0.26 then subtracted $19.50 by 0.26 and got $19.24

$12.74 times 45.5 that will be $579.67 for just one week

If I didn't get it right. Tell me in the comments. I think I got it right.

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3 years ago
The Blackburn family has a square field where they keep their cattle. The area of the field is 40,000ft squared, and mr Blackbur
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<span>If the Blackburn family has a square field where they keep their cattle and then the area of the field is 40,000ft squared, and Mr. Blackburn wants to put a fence diagonally through the field, the length of the fence should be 282.84 ft.</span>
4 0
4 years ago
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Subtract.<br><br> 5/7−2/5<br><br> Enter your answer as a fraction in simplest form
Ira Lisetskai [31]

Answer:

8/35

Step-by-step explanation:

5/7-2/5=25/35-17/35=25-17/35=8/35

7 0
3 years ago
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What is 0.7 times x = 21
guapka [62]

Answer:

x=30

Step-by-step explanation:

0.7x=21

x=21/0.7

x=30

6 0
4 years ago
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Solve: 2x+7/5 - x-3/10 = x+1/15<br>find the value of x and verify the result will RHS ​
choli [55]

Step-by-step explanation:

<h3><u>Given Question :- </u></h3>

Solve for x :-

\dfrac{2x + 7}{5} -  \dfrac{x - 3}{10}  =  \dfrac{x + 1}{15}

\red{\large\underline{\sf{Solution-}}}

Given linear equation is

\rm :\longmapsto\: \dfrac{2x + 7}{5} -  \dfrac{x - 3}{10}  =  \dfrac{x + 1}{15}

\rm :\longmapsto\: \dfrac{2(2x + 7) - (x - 3)}{10}  =  \dfrac{x + 1}{15}

\rm :\longmapsto\: \dfrac{4x + 14 - x  +  3}{10}  =  \dfrac{x + 1}{15}

\rm :\longmapsto\: \dfrac{(4x - x)  + (14 + 3)}{10}  =  \dfrac{x + 1}{15}

\rm :\longmapsto\: \dfrac{3x  + 17}{10}  =  \dfrac{x + 1}{15}

On multiply by 5 on both sides,

\rm :\longmapsto\: \dfrac{3x  + 17}{2}  =  \dfrac{x + 1}{3}

On cross multiplication, we get

\rm :\longmapsto\:3(3x + 17) = 2(x + 1)

\rm :\longmapsto\:9x +51 = 2x + 2

\rm :\longmapsto\:9x  - 2x = 2 - 51

\rm :\longmapsto\:7x = - 49

\bf\implies \:x =  - 7

<h3><u>VERIFICATION</u></h3>

Consider, LHS

\red{\rm :\longmapsto\: \dfrac{2x + 7}{5} -  \dfrac{x - 3}{10}}

On substituting the value of x, we get

\red{\rm \:  =  \:  \dfrac{2( - 7) + 7}{5} -  \dfrac{ - 7 - 3}{10}}

\red{\rm \:  =  \:  \dfrac{ - 14 + 7}{5} -  \dfrac{ - 10}{10}}

\red{\rm \:  =  \:  \dfrac{ - 7}{5}  + 1}

\red{\rm \:  =  \:  \dfrac{ - 7 + 5}{5}}

\red{\rm \:  =  \:  \dfrac{ - 2}{5}}

Consider RHS

\green{\rm :\longmapsto\:\dfrac{x + 1}{15}}

On substituting the value of x, we get

\green{\rm \:  =  \: \dfrac{ - 7 + 1}{15}}

\green{\rm \:  =  \: \dfrac{ - 6}{15}}

\green{\rm \:  =  \: \dfrac{ - 2}{5}}

\rm \implies\:LHS=RHS

HENCE, VERIFIED

5 0
3 years ago
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