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JulijaS [17]
3 years ago
7

Which matrix is singular? A. A B. B C. C D. D

Mathematics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

D. \left[\begin{array}{ccc}-12&-4\\9&3\end{array}\right]

Step-by-step explanation:

In order for a matrix to be singular, the determinant has to be zero.

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Find the slope intercept form of the line passing through (3,9) and (0,3).
ANEK [815]

Answer:

y = 2x +3

Step-by-step explanation:

To find the slope we do (Y1 - Y2)/(X1-X2) aka rise over run

So, m = (9 - 3) / (3 - 0)

m = 2

Now we have y = 2x +b

Notice one of our points is (0,3)

Since the x value of that point is 0, it is the y intercept.

In the slope intercept form b = y-intercept

Therefore b = 3

So, y = 2x + 3

6 0
3 years ago
The apothem is 3V3 units because it is
Reika [66]

Answer:

Opposite the 60-degree angle.

Step-by-step explanation:

5 0
3 years ago
Need to find the direction angle for each vector. #10 and #12 please!
crimeas [40]

Answer:

10)  - 45 degrees

12)  0 degrees

Step-by-step explanation:

10)

Find the x and y components that define the vector that joins C with D:

x-component: -4 - (-8) = - 4 + 8 = 4

y-component:  4 - 8 = -4

use the tangent function to find the angle \theta:

tan(\theta)=\frac{y-comp}{x-comp}=\frac{-4}{4}  = -1\\\theta = -45^o

12)

Find the x and y components that define the vector that joins A with B:

x-component: 7 - 4 = 3

y-component:  - 1 - (-1) = -1 + 1 = 0

use the tangent function to find the angle \theta:

tan(\theta)=\frac{y-comp}{x-comp}=\frac{0}{3}  = 0\\\theta = 0^o

5 0
3 years ago
The height of an ostrich is 20 inches more than 4 times the height of a kiwi. If an ostrich is 108 inches tall, how tall is a ki
pishuonlain [190]
Let the height of the kiwi be x, then the height of the ostrich is 20 + 4x.
20 + 4x = 108
4x = 108 - 20 = 88
x = 88/4 = 22
The height of the kiwi is 22 inches.
6 0
3 years ago
Help me answer this question :((((
ss7ja [257]

Step-by-step explanation:

I cannot give an exact result but I will try.

What it means by this is to continue the graph up to 2010.

Based on its trajectory, you would simply draw the line on.

If I made a prediction on what it would end up on in 2010, I would say 50 percent.

8 0
2 years ago
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