<span>Answer:
Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home.
:
Let s = original speed
then
(s+11) = return speed
:
Write a time equation: Time = distance%2Fspeed
:
Original time = return time + 1 hr
330%2Fs = 330%2F%28%28s%2B11%29%29 + 1
:
Multiply equation by s(s+11) and you have:
330(s+11) = 330s + s(s+11)
:
330s + 3630 = 330s + s^2 + 11s
:
0 = 330s - 330s + s^2 + 11s - 3630
:
A quadratic equation:
s^2 + 11s - 3630 = 0
Factor this to:
(s + 66)(s - 55) = 0
Positive solution
s = 55 mph is original speed.
:
Find the time
330/55 = 6 hr, original time
and
330/66 = 5 hrs, faster time; confirms our solution.</span>
Answer: He would spend 750$ on the entire vacation.
Step-by-step explanation: Simple addition, 350+150 (Always do the two odd ones first) which equals 500, 500+200 equals 700, and 700+50 equals 750, which gives your answer of 750$'s for the whole vacation.
They don't come out even.
As rounded decimals, the two numbers are
<em>5.54138...</em> and <em>-0.54138...</em>
First, we need to equalize the denominator. If the denominator multiplies by (x+1), so does the numerator. If the denominator multiplies by (x-1), so does the numerator.
Look into my attachment at the second row.
Second, because the first fraction and the second fraction have the same denominator, you can join them into one fraction.Look into my attachment at the third row.
Third, simplify the numerator.Look into my attachment at the fourth to the fifth row
Fourth, simplify the denominator.Look into my attachment at the sixth to the seventh row.
Answer:
b. winter wear, appropriate for around 20-45°F
Step-by-step explanation:
When it is 6:00 hours in Honolulu, it is 15:00 hours in London, this means that there are 15 - 6 = 9 hours of difference.
Paul got into London at 12:00 p.m, that is, at 12 - 9 = 3:00 p.m. Friday Honolulu time. Paul’s flight left Honolulu at 2:00 p.m. Thursday, so he spent 25 hours flighting.
When the flight started, the temperature in London was 30 °C, after 25 hours the temperature dropped 25 °C, so it was 30 - 25 = 5 °C.
To convert from °C to °F, we use the following formula:
(x °C × 9/5) + 32 = y °F
Replacing with x = 5
(5 °C × 9/5) + 32 = 41 °F
