7 I think, I’m sorry if I’m wrong
Answer: option d. x = 3π/2Solution:function y = sec(x)
1) y = 1 / cos(x)
2) When cos(x) = 0, 1 / cos(x) is not defined
3) cos(x) = 0 when x = π/2, 3π/2, 5π/2, 7π/2, ...
4) limit of sec(x) = lim of 1 / cos(x).
When x approaches π/2, 3π/2, 5π/2, 7π/2, ... the limit →+/- ∞.
So, x = π/2, x = 3π/2, x = 5π/2, ... are vertical asymptotes of sec(x).
Answer: 3π/2
The figures attached will help you to understand the graph and the existence of multiple asymptotes for y = sec(x).
Step-by-step explanation:
Let Xb be the no of braclets made
Let Xn be the no of necklaces made
Max Z=250Xb + 500Xn (Objective Function)
Subject to
2Xb + 5Xn <= 625 (rubies)
3Xb + 7 Xn <= 800 ( diamonds)
4Xb + 3 Xn <= 700 (Emeralds)
Xb>=0 (non-negativity)
Xn >= 0 (non negativity
The fourth choice - 5/104.
In one cube, there are 3 even numbers - 2,4,6. For two cubes, the total probability is 36.
3*3 / 36 = 9/36
For letters, there are five vowels over 26 letters = 5 / 26
Multiply the two probabilities to get the probability of rolling two even numbers and selecting one of the vowels.
9/36 * 5/26 = 5/104
Answer:
question 12 is answer B
question 13 is -8x^3
Step-by-step explanation:
exponent rule ![\frac{a^m}{a^n} = a^(^m^-^n^)](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5Em%7D%7Ba%5En%7D%20%20%3D%20a%5E%28%5Em%5E-%5En%5E%29)