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nexus9112 [7]
3 years ago
13

Do y'all understand this question if so plz help ASAP....

Mathematics
1 answer:
Afina-wow [57]3 years ago
7 0

Answer:

6394

Step-by-step explanation:

WXYZ

X < Z

Z = ⅔W

W = ⅔Y

Y = 3X

W = ⅔(3X) = 2X

Z = ⅔(2X) = (4/3)X

X has to be a multiple of 3

If X = 3,

Y = 9

Z = 4

W = 6

WXYZ

6394

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For what values of the variable, do the following fractions exist: y^2-1/y+y/y-3
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Answer:

Remember that the division by zero is not defined, this is the criteria that we will use in this case.

1) \frac{y^2 - 1}{y}  + \frac{y}{y - 3}

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For the first fraction, the denominator is zero when y = 0

and for the second fraction, the denominator is zero when y = 3

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we can write this as:

R / {0} U { 3}

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