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maks197457 [2]
3 years ago
9

I need help with my math final!!

Mathematics
2 answers:
tangare [24]3 years ago
8 0

Answer: is 14

Step-by-step explanation: its 14 but i dont know how to explain it

SIZIF [17.4K]3 years ago
3 0

Answer:

8

Step-by-step explanation:

90x5=450

548-450=98

98divede12=8..2

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6x + 2y - 8 = 12x +4y - 16.
Arlecino [84]

Answer:

3x + y = 4

step by step explanation

3 0
2 years ago
I need help on this problem someone please help
Hatshy [7]
The outlier is a because it is the most different value compared to the rest.
5 0
3 years ago
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Algebraic equations
anzhelika [568]

1) 2x + 9  = 2x -5

            9 ≠ -5 ; No solution

2) 2x-  1 = x + 3

   x = 4; One solution x = 4

3) x + 2 = x + 2

   0 = 0; Identity (or all real numbers)

7 0
3 years ago
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Three ratios equivalent to 11/1
Damm [24]

Answer:

21 2

33 3

44 4

Step-by-step explanation:

think of them as equivalent fractions

8 0
3 years ago
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The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
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