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ASHA 777 [7]
2 years ago
12

what is the total number of pencils that Mr Moretti gives to his students if he puts 3 mechanical pencils in each bag

Mathematics
1 answer:
Alexxandr [17]2 years ago
3 0

Answer:

5

Step-by-step explanation:

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Find the height of a rectangular prism if the surface area is 868, the width is 7 and the length is 31.
Aneli [31]

Answer:

D

Step-by-step explanation:

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3 years ago
From the top of a lighthouse the angle of depression of a speed
otez555 [7]

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164m (to 3 s.f.)

Step-by-step explanation:

Please see the attached picture for the full solution.

5 0
2 years ago
Helena is in charge of selling tickets for the upcoming
iogann1982 [59]

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16

Step-by-step explanation:

If you add them all up you get 80. Then you divide it by 5 since there is 5 terms. 80/5 = 16

5 0
3 years ago
Read 2 more answers
Exercises gives the positions s = f(t) of a body moving on a coordinate line, with s in meters and t in seconds.
SashulF [63]

Hi there!

a. Find the displacement by plugging in the values of the interval:

f(2) - f(0) = 0 - 2 = -2 meters.

Average velocity is the slope, thus:

v_{avg} = \frac{f(2) - f(0)}{2 - 0} = \frac{0 - 2}{2 - 0} = -1

The average velocity for the interval is -1 m/s.

b. To find the speed at the endpoints, we must take the derivative to get the velocity equation:

f(t) = t² - 3t +2

f'(t) = 2t - 3, at t = 0, speed = |-3| = 3 m/s. At t = 2, speed = 2(2) - 3 = 1 m/s.

Acceleration is the second derivative, thus:

f''(t) = 2. The acceleration is 2 m/s² for both endpoints.

c. When the body changes direction, the first derivative changes signs. Thus:

0 = 2t - 3

3 = 2t, t = 1.5 sec. This is where the body changes direction.

8 0
2 years ago
JKL has vertices J(3, -5) K(-8, -1) and L(5,1). JKL will be reflected across the line y= -1 to form J'K'L'. Which quadrant will
katen-ka-za [31]

Answer:

The correct answer is second quadrant.

Step-by-step explanation:

Vertices of J ≡ (3 , -5) which shows J is in fourth quadrant. When J is reflected across the line y = -1, the point J moves to first quadrant as J' with coordinates (3 , 3).

Vertices of K ≡ (-8 , -1) which shows K is in third quadrant. When K is reflected across the line y = -1, the point K remains where it is (in the third quadrant) as it is on the line y = -1 only.

Vertices of L ≡ (5 , 1) which shows L is in first quadrant. When L is reflected across the line y = -1, the point L moves to fourth quadrant as L' with coordinates (5 , -3).

Thus each of the first, fourth and third quadrant contains a vertex except the second quadrant.

4 0
3 years ago
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