All categories

2 years ago

2 Points Which of the following is(are) the solution(s) to . x+6 = 2x - 1?

Mathematics

1 answer:

seropon [69]2 years ago

7 0

Answer:

x = 7

Step by step explanation:

minus x on both sides

6 = x -1

add 1 on both sides

x = 7

You might be interested in

78 calories in 3/4 cup, unit rate of calories per cup

MArishka [77]

78/3/4=78x4/3=104
So, the answer is 104

3 0

2 years ago

How do you find the volume of the solid generated by revolving the region bounded by the graphs

d1i1m1o1n [39]

Answer:

About the x axis

$V = 4\pi[ \frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

Step-by-step explanation:

For this case we have the following functions:

$y = 2x^2 , y=0, X=2$

About the x axis

Our zone of interest is on the figure attached, we see that the limit son x are from 0 to 2 and on y from 0 to 8.

We can find the area like this:

$A = \pi r^2 = \pi (2x^2)^2 = 4 \pi x^4$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= 4\pi \int_{0}^2 x^4 dx$

$V = 4\pi [\frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}$

About the y axis

For this case we need to find the function in terms of x like this:

$x^2 = \frac{y}{2}$

$x = \pm \sqrt{\frac{y}{2}}$ but on this case we are just interested on the + part $x=\sqrt{\frac{y}{2}}$ as we can see on the second figure attached.

We can find the area like this:

$A = \pi r^2 = \pi (2-\sqrt{\frac{y}{2}})^2 = \pi (4 -2y +\frac{y^2}{4})$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \pi \int_{0}^8 2-2y +\frac{y^2}{4} dy$

$V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}$

About the line y=8

The figure 3 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (8-2x^2)^2 = \pi (64 -32x^2 +4x^4)$

And we can find the volume with this formula:

$V = \int_{a}^b A(x) dx$

$V= \pi \int_{0}^2 64-32x^2 +4x^4 dx$

$V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}$

About the line x=2

The figure 4 attached show the radius. We can find the area like this:

$A = \pi r^2 = \pi (\sqrt{\frac{y}{2}})^2 = \pi\frac{y}{2}$

And we can find the volume with this formula:

$V = \int_{a}^b A(y) dy$

$V= \frac{\pi}{2} \int_{0}^8 y dy$

$V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi$

6 0

2 years ago

Guys last one then I finished let's gi

Ulleksa [173]

Jack gives more money

7 0

3 years ago

If the product of a number and -4 is subtracted from the number, the result is 3 more than the number. Find the number

lesya [120]

Answer: The number is 0.75 or 3/4

Step-by-step explanation:

let x = the number.

Now set up an equation: The product of a number (x) and -4 = -4x. So -4x is subtracted from the number - x. x-(-4x)

Then, that equals 3 more than the number (x) = x+3

So the equation is x-(-4x)=x+3.

Then, solve the equation!

x-(-4x)=x+3

x+4x=x+3 (Distribute the negative to the parentheses)

5x=x+3 (Combine like terms)

4x=3 (Get the Xs on one side by subtracting x from both sides)

x=0.75 or 3/4 (divide by the coefficiant, 4, on both sides)

3 0

2 years ago

Read 2 more answers

Please help me with this question i will mark you as the best answer

statuscvo [17]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers