2 years ago

Convert the rectangular equation to polar form. assume a is less than 0. x=10

Mathematics

1 answer:

Ilia_Sergeevich [38]2 years ago

5 0

R cos(t) =10 r = 10/cos(t)

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which metod is most efficent in solving a system of linear equations when the two equations have x-values with opposite coeffici

telo118 [61]

Answer:

See below

Step-by-step explanation:

Just add the two equations together....this will eliminate 'x' and you can then solve for 'y'

Use this value of 'y' in one of the equations to calculate the value of 'x'

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1 year ago

Expand and simplify (2c+1)(2c+3)

Mandarinka [93]

The answer would be 4c^2+8c+3

The arrow stands for squared off you didn’t already know but these are very easy to solve because you just multiply it out

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1 year ago

Richard has enrolled in a 401(k) savings plan. He intends to deposit $250 each month; his employer does not contribute to his ac

astraxan [27]

Answer:

Richard will have $60,000 in his account in 20 years.

Step-by-step explanation:

(1) Multiply $250 x 12

(2) Multiply the answer of $250 x 12 which is 3000 by 20

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2 years ago

The longer leg of a right triangle is 6cm longer than the shorter leg and also 1cm longer than the hyptenese. find the perimeter

CaHeK987 [17]

X - a leg (x > 6);
x - 6 - a leg;
x + 1 - a <span>hypotenuse;</span>
Use the Pythagorean theorem
$(x+1)^2=x^2+(x-6)^2$

Use: $(a\pm b)^2=a^2\pm2ab+b^2$

$x^2+2x+1=x^2+x^2-12x+36\ \ \ |-x^2-2x-1\\\\x^2-14x+35=0\ \ \ |-35\\\\x^2-14x=-35\\\\x^2-2\cdot x\cdot7=-35\ \ \ |+7^2\\\\x^2-2\cdot x\cdot7+7^2=-35+7^2\\\\(x-7)^2=14\iff x-7=\pm\sqrt{14}\ \ \ |+7\\\\x=7-\sqrt{14} < 6;\ x=7+\sqrt{14}$

$x=7+\sqrt{14}\\x-6=1+\sqrt{14}\\x+1=8+\sqrt{14}$

The perimeter:

$7+\sqrt{14}+1+\sqrt{14}+8+\sqrt{14}=16+3\sqrt{14}$

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2 years ago

Please help me with this question

zubka84 [21]

Answer: c. f - 3 + 6d

Explanation: 5d - d + 4 + 2d - 5f - 6f - 7
- 5f - 6f = f
4 - 7 = -3
5d - d = 4d, 4d + 2d = 6d

4 0

1 year ago