Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
Answer:
129
Step-by-step explanation:
The easiest thing to do would be an equation.
Since the value is decreasing by 6 each time you have -6x
-6x+?=?
Next thing you do, to get the y-intercept, would be to add 6 to the 309, which is the first term in order to get the zeroth term. This would make 315 the y-intercept
-6x+315=?
To solve for the 31st term, plug in 31 for x to get 129
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9 of the dogs at the shelter are puppies.
Answer:
86°
Step-by-step explanation:
Given:
A = (6x + 10)°
B = (4x +30)°
Two angles are supplementary if they sum up to 180° ;
A + B = 180°
Now insert the parameters and solve;
6x + 10 + 4x +30 = 180
10x + 40 = 180
10x = 140
x = 14
So;
B = (4x +30)° = 4(14) + 30 = 86°