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alexandr402 [8]

3 years ago

10

A football team lost 4 yards on each of 2 plays, gained 14 yards on the third play, and lost 5 yards on the fourth play. Write a

nd find the value of an integer expression to find the change in their field position.

1 answer:

Rzqust [24]3 years ago

3 0

The change in field position is one

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Can someone help me with this please? I will mark you brainliest

lina2011 [118]

Answer:

On the vertical axis, place frequencies. Label this axis "Frequency".

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On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

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Step-by-step explanation:

6 0

2 years ago

Tiana's math test score are 85 and 91 . She has one more test left. In order to earn and A, her average test score must be at le

Zanzabum

85 + 91 + x ÷3 ≥94

You didn't give any choices but this represents the problem.

3 0

3 years ago

Lane is 10 times Mels age. If the difference in their age is 27, how old is Mel?

Sergeu [11.5K]

The answer is 3!

explanation; 3x10 equals 30. the difference is 27 years and 30-3=27!

8 0

3 years ago

Read 2 more answers

Please answer this! I really suck at math and I need to do well.

Mariulka [41]

I believe it would be G.

5 0

2 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two ind

liberstina [14]

Answer:

Step-by-step explanation:

Hello!

You have two populations of interest and want to compare them. If you define the study variables as:

X₁: average hourly wages of an employee of the Downtown store.

n₁= 25

X[bar]₁= $9

S₁= $2

X₂: average hourly wages of an employee of the North Mall store.

n₂= 20

X[bar]₂= $8

S₂= $1

Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:

95% CI for μ₁ - μ₂

(X[bar]₁-X[bar]₂) ± $t_{n_1+n_2-2; 1-\alpha /2} * (Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } )$

$Sa^2= \frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}$

$Sa^2= \frac{24*4+19*1}{25+20-2}= 2.67$

Sa= 1.64

$t_{n_1-n_2-2;1-\alpha /2} = t_{43; 0.975} = 2.017$

(9-8)±2.017* $(1.64*\sqrt{\frac{1}{25} +\frac{1}{20} } )$

[0.007636;1.9923]

I hope it helps!

6 0

2 years ago