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3 years ago

A net and the prism it will form when it is folded are shown below.

Mathematics

2 answers:

AveGali [126]3 years ago

6 0

<h3>Surface area of the prism is 724 square centimeters</h3>

Solution:

The surface area of prism is given as:

$Surface\ Area = 2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the prism

L = 12 cm

W = 11 cm

H = 10 cm

Find area of base

$B = LW\\\\B = 12 \times 11\\\\B = 132$

Find the perimeter of the base P

$P=2(L+W)\\\\\ P=2(12+11)=46\ cm$

Find the surface area SA

$Surface\ Area =2(132)+(46)(10)\\\\Surface\ Area = 724\ cm^{2}$

Thus the surface area of the prism is 724 square centimeters

allochka39001 [22]3 years ago

4 0

Answer:

A or 724

Step-by-step explanation:

So I took the test.

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Matt is cutting quilt squares measuring 3 inches on each side. He wants to use them to make a rectangular wall hanging measuring

Andrei [34K]

Answer:

Matt will need 10176 square quilts to cover the wall

Step-by-step explanation:

To answer this perfectly, we will have to first convert everything to the same unit.

dimensions of the quilt squares = 3 inches

Length of the wall = 1 yard = 36 inches

Breadth of the wall = 212 feet = 2544 inches.

The next step, is to find the area of the wall that Matt is covering.

Area of wall = length X breadth = 36 X 2544 = $91584in ^{2}$

We will also find the area of the square quilts. This is given as length X length = $3^{2}$ = $9 in^{2}$

to get the number of square quilts that will cover that area, we will have to divide the area of the wall by the area of the quilts

= 91584 /9 = 10176 quilts

Matt will need 10176 quilts to cover the wall

5 0

2 years ago

What is the perimeter of a parallelogram, if its area is 24 cm^2 and and the distances between the point of intersection of the

Stells [14]

Answer is 20 cm i guess

4 0

2 years ago

Question 6 of 10

Vinil7 [7]

62 triangle a and 59 triangle b

6 0

2 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

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3 0

11 months ago

What is the true solution In 20+In 5=2 In x?

S_A_V [24]

Answer:

x = 10

Step-by-step explanation:

Using the rules of logarithms

• log x + log y ⇔ log(xy)

• log $x^{n}$ ⇔ n log x

• log x = log y ⇒ x = y

Given

ln20 + ln5 = 2 lnx , then

ln(20 × 5) = ln $x^{2}$

ln 100 = ln $x^{2}$ , hence

x² = 100 ( take the square root of both sides )

x = 10

7 0

2 years ago