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skad [1K]
3 years ago
5

Juan is a teacher and takes home 618 papers to grade over the weekend. He can grade

Mathematics
1 answer:
jek_recluse [69]3 years ago
5 0

Answer:

576

Step-by-step explanation:

6 papers an hour. 7 hours spent grading.

So 7•6 = 42

618-42

576

Hope this helps

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Lcm of 10, 20 and 110
mart [117]

Answer:

220

Step-by-step explanation:

110 cannot be the lcm for 20 but 10 and 110

so 220 can be the lcm for 20, 10, and 110

hope this helps

6 0
3 years ago
What is the value of the expression 2 + 32 ⋅ (4 − 1)? <br> A: 24<br> B: 29 <br> C: 33 <br> D: 37
Paul [167]

For this case we have the following expression:

2 + 3 ^ 2 * (4 - 1)

Rewriting the expression we have:

1) First we subtract the numbers within the parenthesis:

2 + 3 ^ 2 * (3)

2) Then, we solve the exponents:

2 + 9 * (3)

3) Then, multiplication:

2 + 27

4) Finally, the addition of numbers is made:

29

Answer:

the value of the expression is:

B: 29

3 0
4 years ago
Read 2 more answers
The lid for a circular plastic food container has a diameter of 9 cm.
Levart [38]
If the diameter is 9 cm the radius is 4.5 cm (half the diameter).  The area of a circle is given by the formula:  4πr^2, where π is the constant ratio of circumference to diameter (3.14159...).

3.14 cm x 4.5 cm = 14.13 cm^2.  Remember, the units must be squared to represent area.  14.13 is extended to the nearest hundredth.
5 0
3 years ago
The tallest man in medical history was Robert Wadlow. He was 12 4/5times as tall as he appears in a Book of Reords photograph. H
kobusy [5.1K]
Hey! your answer would be 96 inches which is eight feet!

8 0
3 years ago
What is the frequency of yellow
Zina [86]

Answer:

5.131 × 10¹⁴  Hz

Step-by-step explanation:

<u>Planck relation</u>

\large\boxed{E = hf}

where:

  • E = Energy of the photon (J).
  • h = Planck's constant (J · s).
  • f = frequency of light produced (Hz).

Given values:

  • E = 3.4 × 10⁻¹⁹ J
  • h = 6.626 × 10⁻³⁴ J · s

Substitute the given values into the formula and solve for f:

\implies 3.4 \times 10^{-19}=(6.626 \times 10^{-34})f

\implies f=\dfrac{3.4 \times 10^{-19}}{6.626 \times 10^{-34}}

\implies f=\dfrac{3.4}{6.626} \times \dfrac{10^{-19}}{10^{-34}}

\implies f=0.5131\times 10^{(-19-(-34))}

\implies f=0.5131 \times 10^{15}

\implies f=5.131 \times 10^{14}

8 0
1 year ago
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