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3 years ago

Solve the inequality (29/289)z<(16/161)z

Mathematics

2 answers:

NeTakaya3 years ago

8 0

Answer:

$z < 0$

Step-by-step explanation:

Given:

$\frac{29}{289}z$

Required:

Solve for z

Follow the following steps:

Step 1: Rewrite expression

$\frac{29z}{289}$

Step 2: Multiply both sides of the inequality by (289)(161)

$(161)(289)\frac{29z}{289}$

Step 3: Simplify Expression

$161 * 29z< 289 * 16z$

Step 4: Multiply

$4669 z< 4624 z$

Step 5: Collect Like Terms

$4669 z - 4624 z< 0$

Step 6: Subtract

$45z< 0$

Step 7: Divide both sides by 45

$\frac{45z}{45} < \frac{0}{45}$

$z < 0$

Hence, the resul of $\frac{29}{289}z$ is $z < 0$

stellarik [79]3 years ago

4 0

is that what you looking for

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<h3>Given :</h3>

Base of triangle = 7 yd
Height of triangle = 10 yd

$\\ \\$

Area of triangle

$\\ \\$

We know:-

When base and height of triangle is given we use this formula:

$\bigstar \boxed{ \rm Area \: of \: triangle = \frac{base \times height}{2} }$

$\\ \\$

So:-

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{base \times height}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 10}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times2 }{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times\cancel2 }{\cancel2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times1 }{1} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5$

$\\ \\$

$\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2} \\$

$\\ \\$

$\therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^{ \red2} }}$

$\\ \\$

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