Nice;-;
does jared need help carrying it
Answer:
0.36878
Step-by-step explanation:
Given that:
Mean number of miles (m) = 2135 miles
Variance = 145924
Sample size (n) = 40
Standard deviation (s) = √variance = √145924 = 382
probability that the mean of a sample of 40 cars would differ from the population mean by less than 29 miles
P( 2135 - 29 < z < 2135 + 29)
Z = (x - m) / s /√n
Z = [(2106 - 2135) / 382 / √40] < z < [(2164 - 2135) / 382 / √40]
Z = (- 29 / 60.399503) < z < (29 / 60.399503)
Z = - 0.4801364 < z < 0.4801364
P(Z < - 0.48) = 0.31561
P(Z < - 0.48) = 0.68439
P(- 0.480 < z < 0.480) = 0.68439 - 0.31561 = 0.36878
= 0.36878
As we know that
x=x0*[1/2]n
putting the values
375=3000*[1/2]n
375/3000=<span>[1/2]n
</span>1/8=<span>[1/2]n
simplify
[1/2]3=</span><span>[1/2]n
by cancelling them
so n=3
so it will take 3 minutes
hope it helps</span>
