A) Yes, the two events are independent because P(NF|PB) = P(NF).
<span>1) Find P(E1UE2)
E1 probability= 1/2</span>
<span>There are 26 red cards in a 52 card deck, so the probability of choosing a red card is = 26/52 = 1/2
E2 probability= 12/ 52 or 3/13</span>
<span>The face cards are: Jacks, Queens, and <span>Kings. There are four suits, so in each suit there are one jack, one queen and one king. The probability is 3 x 4= 12 divided by the total number of cards.
2)</span></span><span>the probability of drawing a blue ball on the first draw: 4 /10
</span>the probability of drawing a white ball on the second drawn: 6/9 (because there is less one ball from the previous draw).
the probability of the cases together is 4/15 ( 4 /10 x 6/9) <span>since they are independent cases.</span>
Common difference is -2-5 = -7
first term is 5
a_50 = 5 -7(50-1) = -338
2) d = 3 - (-7) = 10
a = -7
a_110 = -7 + 10(110 - 1) = 1083
d = -27 - (-22) = -5
second -7 - 5= -12
third = -12 - 5 = -17
The simplified answer is 27m^2
