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Dominik [7]
3 years ago
11

When using the right-hand rule to determine the direction of the magnetic force on a charge, which part of the hand points in th

e
direction that the charge is moving?
Physics
1 answer:
xeze [42]3 years ago
6 0

Answer:index

Explanation:

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The cheetah is one of the fastest-accelerating animals, because it can go from rest to 19.6 m/s (about 44 mi/h) in 2.9 s. If its
Vitek1552 [10]

Answer:

a)P =14288.4 W

b)P = 19.16  horsepower

Explanation:

Given that

m= 108 kg

Initial velocity ,u= 0 m/s

Final velocity ,v= 19.6 m/s

t= 2.9 s

Lets take acceleration of Cheetah is a m/s²

We know that

v= u  + a t

19.6 = 0 + a x 2.9

a= 6.75 m/s²

Now force F

F= m a

F= 108 x 6.75 N

F= 729 N

Now the power P

P = F.v

P = 729 x 19.6 W

P =14288.4 W

We know that

1 W= 0.0013  horsepower

P = 19.16  horsepower

P =14288.4 W

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4 years ago
Which factor has the least impact on the potential energy or kinetic energy of an object
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at its LOWEST point oh height. </span>
5 0
4 years ago
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If the pig can move the car 30 meters in 10 seconds then what is the speed for the car
mote1985 [20]

Answer:

3 mps

Explanation:

So we want to convert this into a unit rate. So we take 30/10=3. So 3 meters per second.

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3 years ago
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HELP ME ASAP ITS PHYSICS AND it’s finding the kinetic energy SHOW WORKKK
lord [1]

k = 1/2 × m × v^2

_____________________________

1. k = 1/2 × 60 × ( 10 )^2

k = 30 × 100

k = 3000 j

_____________________________

2. k = 1/2 × 60 × ( 9 )^2

k = 30 × 81

k = 2430 j

_____________________________

3. k = 1/2 × 60 × ( 4 )^2

k = 30 × 16

k = 480 j

_____________________________

4. k = 1/2 × 60 × ( 6 )^2

k = 30 × 36

k = 1080 j

______________________________

5. k = 1/2 × 60 × ( 0 ) ^2

k = 30 × 0

k = 0 j

6 0
3 years ago
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Calculate the magnitude of the normal force on a 25.2 kg block in the following circumstances. (Enter your answers in N.) HINT (
irga5000 [103]

Answer:

when the body is resting N = 246.96 N

when the body is resting on a tilted surface N = 212.12 N.

when the body is in a elevator N = 317.036 N

Explanation:

when the block is resting on a stationary surface the normal force is balanced by the weight of the body.

weight of the body = mg = 25.2×9.8 = 246.96 N

therefore normal force = 246.98 N.

when the block is resting on a tilted surface the normal force will be balanced by the \cos \theta component of the weight where Ф is the angle of inclination.

therefore N = mg\cos \Phi

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when the block is resting on a elevator that is accelerated upward the normal force will be the sum of weight and force due to acceleration ma

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N = 317.036 N

5 0
4 years ago
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