Answer:
a)P =14288.4 W
b)P = 19.16 horsepower
Explanation:
Given that
m= 108 kg
Initial velocity ,u= 0 m/s
Final velocity ,v= 19.6 m/s
t= 2.9 s
Lets take acceleration of Cheetah is a m/s²
We know that
v= u + a t
19.6 = 0 + a x 2.9
a= 6.75 m/s²
Now force F
F= m a
F= 108 x 6.75 N
F= 729 N
Now the power P
P = F.v
P = 729 x 19.6 W
P =14288.4 W
We know that
1 W= 0.0013 horsepower
P = 19.16 horsepower
P =14288.4 W
<span>
at its LOWEST point oh height. </span>
Answer:
3 mps
Explanation:
So we want to convert this into a unit rate. So we take 30/10=3. So 3 meters per second.
k = 1/2 × m × v^2
_____________________________
1. k = 1/2 × 60 × ( 10 )^2
k = 30 × 100
k = 3000 j
_____________________________
2. k = 1/2 × 60 × ( 9 )^2
k = 30 × 81
k = 2430 j
_____________________________
3. k = 1/2 × 60 × ( 4 )^2
k = 30 × 16
k = 480 j
_____________________________
4. k = 1/2 × 60 × ( 6 )^2
k = 30 × 36
k = 1080 j
______________________________
5. k = 1/2 × 60 × ( 0 ) ^2
k = 30 × 0
k = 0 j
Answer:
when the body is resting N = 246.96 N
when the body is resting on a tilted surface N = 212.12 N.
when the body is in a elevator N = 317.036 N
Explanation:
when the block is resting on a stationary surface the normal force is balanced by the weight of the body.
weight of the body = mg = 25.2×9.8 = 246.96 N
therefore normal force = 246.98 N.
when the block is resting on a tilted surface the normal force will be balanced by the
component of the weight where Ф is the angle of inclination.
therefore N = mg
N= 212.12 N.
when the block is resting on a elevator that is accelerated upward the normal force will be the sum of weight and force due to acceleration ma
therefore N = 246.98 + 25.2×2.78
N = 317.036 N