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3 years ago

What is the length of a simple pendulum oscillating on Earth with a period of 0.5s?

Physics

1 answer:

Akimi4 [234]3 years ago

4 0

Explanation:

don't u know that a pendulum can't oscillate on earth idiot you don't have senses or wgat. just wrote the question with senses gone to graze the grass in the garden.

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A particle has a charge of q = +4.9 μC and is located at the origin. As the drawing shows, an electric field of Ex = +242 N/C ex

irina1246 [14]

$F_{E_x}=1.19\cdot 10^{-3}N$ (+x axis)

$F_{B_x}=0$

$F_{B_y}=0$

$F_{E_x}=1.19\cdot 10^{-3} N$ (+x axis)

$F_{B_x}=0$

$F_{B_y}=3.21\cdot 10^{-3}N$ (+z axis)

$F_{E_x}=1.19\cdot 10^{-3} N$ (+x axis)

$F_{B_x}=3.21\cdot 10^{-3} N$ (+y axis)

$F_{B_y}=3.21\cdot 10^{-3}N$ (-x axis)

Explanation:

The electric force exerted on a charged particle is given by

$F=qE$

where

q is the charge

E is the electric field

For a positive charge, the direction of the force is the same as the electric field.

In this problem:

$q=+4.9\mu C=+4.9\cdot 10^{-6}C$ is the charge

$E_x=+242 N/C$ is the electric field, along the x-direction

So the electric force (along the x-direction) is:

$F_{E_x}=(4.9\cdot 10^{-6})(242)=1.19\cdot 10^{-3} N$

towards positive x-direction.

The magnetic force instead is given by

$F=qvB sin \theta$

where

q is the charge

v is the velocity of the charge

B is the magnetic field

$\theta$ is the angle between the directions of v and B

Here the charge is stationary: this means $v=0$ , therefore the magnetic force due to each component of the magnetic field is zero.

In this case, the particle is moving along the +x axis.

The magnitude of the electric force does not depend on the speed: therefore, the electric force on the particle here is the same as in part a,

$F_{E_x}=1.19\cdot 10^{-3} N$ (towards positive x-direction)

Concerning the magnetic force, we have to analyze the two different fields:

- $B_x$ : this field is parallel to the velocity of the particle, which is moving along the +x axis. Therefore, $\theta=0^{\circ}$ , so the force due to this field is zero.

$- B_y$ : this field is perpendicular to the velocity of the particle, which is moving along the +x axis. Therefore, $\theta=90^{\circ}$ . Therefore, $\theta=90^{\circ}$ , so the force due to this field is:

$F_{B_y}=qvB_y$

where:

$q=+4.9\cdot 10^{-6}C$ is the charge

$v=345 m/s$ is the velocity

$B_y = +1.9 T$ is the magnetic field

Substituting,

$F_{B_y}=(4.9\cdot 10^{-6})(345)(1.9)=3.21\cdot 10^{-3} N$

And the direction of this force can be found using the right-hand rule:

- Index finger: direction of the velocity (+x axis)

- Middle finger: direction of the magnetic field (+y axis)

- Thumb: direction of the force (+z axis)

As in part b), the electric force has not change, since it does not depend on the veocity of the particle:

$F_{E_x}=1.19\cdot 10^{-3}N$ (+x axis)

For the field $B_x$ , the velocity (+z axis) is now perpendicular to the magnetic field (+x axis), so the force is

$F_{B_x}=qvB_x$

And by substituting,

$F_{B_x}=(4.9\cdot 10^{-6})(345)(1.9)=3.21\cdot 10^{-3} N$

And by using the right-hand rule:

- Index finger: velocity (+z axis)

- Middle finger: magnetic field (+x axis)

- Thumb: force (+y axis)

For the field $B_y$ , the velocity (+z axis) is also perpendicular to the magnetic field (+y axis), so the force is

$F_{B_y}=qvB_y$

And by substituting,

$F_{B_y}=(4.9\cdot 10^{-6})(345)(1.9)=3.21\cdot 10^{-3} N$

And by using the right-hand rule:

- Index finger: velocity (+z axis)

- Middle finger: magnetic field (+y axis)

- Thumb: force (-y axis)

3 0

4 years ago

This is my question

aliya0001 [1]

Answer: left and applied force

Explanation:

5 0

3 years ago

A diver, of mass 40kg, climbs up to a diving platform 1.25m high. What’s her KE

Leona [35]

Explanation:

The formula for KE ( Kinetic Energy ) is : 1/2 mv²

Solution:

First we solve for v ( velocity ) using the formula 2gh, where g is gravity [ 9.8 m/s² ] and h is height [ 1.25 m ]

= 2 ( 9.8 m/s² × 1.25 m ) = 24.5 m/s

The velocity is 24.5 m/s.

Now solve for KE using the formula 1/2 mv²

= 1/2 ( 40 kg × 24.5m/s ² )

= 1/2 ( 40 kg × 600.25 )

= 1/2 ( 24,010 )

= 12,005 Joules

The diver's kinetic energy is 12,005 J.

6 0

2 years ago

Que es la natación paralímpica???

Leni [432]

Answer:

Paralympic swimming is an adaptation of the sport of swimming for athletes with disabilities. Paralympic swimmers compete at the Summer Paralympic Games and at other sports competitions throughout the world. The sport is governed by the International Paralympic Committee.

8 0

3 years ago

Why aren’t hydrogen fuel cell cars currently available to the public?

olga55 [171]

For one thing, hydrogen gas or fuel is really expensive compared to present diesel and gasoline. There's no point in actually investing in them since economy will not improve otherwise. Gasoline stations will also have to adjust to how tricky hydrogen gas will be to support and store with ease. It's dangerous also to the driver, passengers and our environment.

4 0

4 years ago

Read 2 more answers