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liq [111]
2 years ago
6

HELP ME ASAP ITS PHYSICS AND it’s finding the kinetic energy SHOW WORKKK

Physics
2 answers:
lord [1]2 years ago
6 0

k = 1/2 × m × v^2

_____________________________

1. k = 1/2 × 60 × ( 10 )^2

k = 30 × 100

k = 3000 j

_____________________________

2. k = 1/2 × 60 × ( 9 )^2

k = 30 × 81

k = 2430 j

_____________________________

3. k = 1/2 × 60 × ( 4 )^2

k = 30 × 16

k = 480 j

_____________________________

4. k = 1/2 × 60 × ( 6 )^2

k = 30 × 36

k = 1080 j

______________________________

5. k = 1/2 × 60 × ( 0 ) ^2

k = 30 × 0

k = 0 j

asambeis [7]2 years ago
3 0

the ans is like this

1 4

2 5

3

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A 20-kg block slides down a fixed rough curved track The block has a speed of 5 0 m/s after its height above a horizontal surfac
Crank

Answer:

U = 102.8 J (100 J to two significant digits)

Explanation:

potential energy converted = 20(9.8)(1.8) = 352.8 J

kinetic energy at base of track = ½(20)5.0² = 250 J

energy (work) of friction 352.8 - 250 = 102.8 J

8 0
3 years ago
He __________ uses a series of gears to adjust the output speed of the engine.
Verizon [17]
Hey /人 ◕ ‿‿ ◕ 人\
The answer is transmission

uses a series of gears to transmit power to facilitate changes in speed .


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4 0
3 years ago
The energies of electrons are said to be quantized. Explain what this means. please explain.
sleet_krkn [62]
To move from one energy<span> level to another, an </span>electron<span> must gain or lose just the right amount of </span>energy<span>. </span>Electrons are said to be quantized<span> because they need a quantum of </span>energy<span> to move to a different sublevel. ... When atoms absorb </span>energy<span>, </span>electrons<span> move into higher </span>energy<span> levels.</span>
8 0
3 years ago
A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec
olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

h=u't+\dfrac{1}{2}gt^2

h=\dfrac{1}{2}gt^2

h=\dfrac{1}{2}\times 9.8\times (4.3)^2

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

5 0
3 years ago
A wave can be described as?
aleksley [76]

Answer:

<em>B) The disturbance of particles in an area.</em>

Explanation:

<em>A wave involves transmission of  energy from one place to another by the actual disturbance of the particles of the medium.</em>

<em />

6 0
2 years ago
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