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liq [111]
3 years ago
6

HELP ME ASAP ITS PHYSICS AND it’s finding the kinetic energy SHOW WORKKK

Physics
2 answers:
lord [1]3 years ago
6 0

k = 1/2 × m × v^2

_____________________________

1. k = 1/2 × 60 × ( 10 )^2

k = 30 × 100

k = 3000 j

_____________________________

2. k = 1/2 × 60 × ( 9 )^2

k = 30 × 81

k = 2430 j

_____________________________

3. k = 1/2 × 60 × ( 4 )^2

k = 30 × 16

k = 480 j

_____________________________

4. k = 1/2 × 60 × ( 6 )^2

k = 30 × 36

k = 1080 j

______________________________

5. k = 1/2 × 60 × ( 0 ) ^2

k = 30 × 0

k = 0 j

asambeis [7]3 years ago
3 0

the ans is like this

1 4

2 5

3

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Answer:

a)

Explanation:

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        x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}   (1)

  • Since the car starts from rest, v₀ =0.
  • We know the value of t = 5 sec., but we need to find the value of a.
  • Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:

       a_{c} =\frac{v_{fc}}{t} = \frac{20m/s}{5s} = 4 m/s2  (2)

  • Replacing a and t in (1):

       x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}  = \frac{1}{2}*a*t^{2} = \frac{1}{2}* 4 m/s2*(5s)^{2} = 50.0 m.  (3)

  • Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
  • Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:

       a_{t} =\frac{-v_{to}}{t} = \frac{-20m/s}{10s} = -2 m/s2  (4)

  • Replacing v₀, at and t in (1), we have:

       x_{ft} = 20m/s*10.0s + \frac{1}{2}*(-2 m/s2)*(10.0s)^{2} = 200m -100m = 100.0m   (5)

  • Therefore, as the truck travels twice as far as the car, the right answer is a).
7 0
3 years ago
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aksik [14]
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3 0
3 years ago
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Allushta [10]

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Explanation:

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7 0
3 years ago
In the periodic table, similar elements are arranged in vertical columns called
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Answer:

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Explanation:

H = mc∅

Above equation can be used here to find the answer to the question. this equation gives us the relationship between the heat energy supplied to a material and the temperature difference that the material would go through according to its mass.

here H is the Heat energy supplied to the material. m is the mass of the material. c is the specific heat capacity of the material and ∅ is the temperature difference applied to the material. we are given that H= 337,500J , m = 50 kg and ∅ = 15 °C. so from the equation now we can calculate the value of c. after calculating c we can find the material because c is an unique value for a particular material. no two materials have the same c value.

c = 337500/(50*15)

c = 450 J/(kg°C) - Iron (google the heat capacity value to find the answer Iron)

8 0
3 years ago
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