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ankoles [38]
3 years ago
11

If element X has 39 protons, how many electrons does it have?

Physics
1 answer:
lara31 [8.8K]3 years ago
8 0
Hi. There would be 39 electrons since in atoms there are the same amount of both protons and electrons. Good luck.
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Which city has already hosted the Olympic Games three times?
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London, it has hosted the 1908, 1948 and the 2012 summer olympics
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4 years ago
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Explain the Kinetic Theory of Matter<br> and use an example from everyday life
abruzzese [7]

Answer:

The Kinetic Theory of Matter or KTM as i will call it, states that every object is made of many many small particles (humans are made of sextillions of atoms), and that they are constantly moving and bumping each other. The degree to which the particles move is determined by the amount of energy they have and their relationship to other particles.

An example would be Brownian Motion- the random movement of dust particles because of collisions with "air" molecules and how gases behave i.e. Boyle's, Charles', and Gay-Lussac's Laws.

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3 years ago
What is a cone of depression
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4 years ago
Physics in motion Unit 6A The nature of waves
Daniel [21]

#1

length of one complete wave shape is known as wavelength

#2

Frequency is defined as number of oscillations per second or number of waves passing through a point in one second.

#3

One Time period is the time to cover one complete wavelength distance by the wave

#4

relation between time period and frequency is given as

f = \frac{1}{T}

#5

Time period of simple pendulum is given as

T = 2\pi \sqrt{\frac{L}{g}}

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#6

amplitude of the wave is the height above the axis to which particle can attain its maximum position or its maximum height on y axis is amplitude

4 0
3 years ago
an object of mass 0.5kg at rest, started to fall aheigh of 180cm from the surface of earth. it's momentum when it reaches the ea
kupik [55]

Answer:

m=0.5kg

h = 180 cm =1.8 mh=180cm=1.8m

Initial potential energy of the object is:

E_p=m*g*hE

p

​ =m∗g∗h

Kinetic energy at the surface:

E_k=\frac{mv^2}{2}E

k

​  =

2

mv

2

According to the law of conservation of energy (assuming no air resistance):

E_p = E_kE

p

​  =E

k

​mgh=\frac{mv^2}{2}mgh=

2

mv

2

Solving for v:

v=\sqrt{2gh}v=

2gh

​

p=mvp=mv

So,

p= m*v = m\sqrt{2gh}p=m∗v=m

2gh

​

Calculating:

p= 0.5\sqrt{2*9.8*1.8}\approx 2.97 \frac{kg*m}{s}p=0.5

2∗9.8∗1.8

​ ≈2.97

s

kg∗m

​ Answer:

p \approx 2.97 \frac{kg*m}{s}p≈2.97

s

kg∗m

​

4 0
3 years ago
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