Answer:
the boat would be deeped by 3200 m
Explanation:
Given that
The boat arrives back after 4 seconds
And, the speed of the sound in water is 1,600 m/s
We need to find out how much deep is the water
So,
As we know that
Distance = ( speed × time) ÷ 2
Here we divided by 2 because the boat arrives back
= (1600 × 4) ÷ 2
= 3200 m
Therefore the boat would be deeped by 3200 m
Answer:
y = 54.9 m
Explanation:
For this exercise we can use the relationship between the work of the friction force and mechanical energy.
Let's look for work
W = -fr d
The negative sign is because Lafourcade rubs always opposes the movement
On the inclined part, of Newton's second law
Y Axis
N - W cos θ = 0
The equation for the force of friction is
fr = μ N
fr = μ mg cos θ
We replace at work
W = - μ m g cos θ d
Mechanical energy in the lower part of the embankment
Em₀ = K = ½ m v²
The mechanical energy in the highest part, where it stopped
= U = m g y
W = ΔEm = - Em₀
- μ m g d cos θ = m g y - ½ m v²
Distance d and height (y) are related by trigonometry
sin θ = y / d
y = d sin θ
- μ m g d cos θ = m g d sin θ - ½ m v²
We calculate the distance traveled
d (g syn θ + μ g cos θ) = ½ v²
d = v²/2 g (sintea + myy cos tee)
d = 9.8 12.6 2/2 9.8 (sin16 + 0.128 cos 16)
d = 1555.85 /7.8145
d = 199.1 m
Let's use trigonometry to find the height
sin 16 = y / d
y = d sin 16
y = 199.1 sin 16
y = 54.9 m
Four red flags
The load being carried poses a hazard to vehicles in the proximity of the load-carrying vehicle, and so it is mandatory by law for the vehicle to make the load more visible. At night time, the load is marked using red lights, as flags would not be visible then.
Since the plane is traveling at 100m/s horizontal to the surface of the earth, the crate will always have this horizontal velocity (neglecting air resistance) until it hits the ground. So the answer is 100m/s. Note the vertical speed continues to change as the crate accelerates downward toward earth (again neglecting air effects)
Answer:
A)- SHORT WAVELENGTH AND LOW AMPLITUDE.
Explanation:
high pitch sound waves possess low wavelength and
quiet sound means that amplitue of the sound wave is low.
therefore option A matches the answer most.