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3 years ago

This is data from a visible satellite image. What types of weather conditions are associated with the image?

Physics

2 answers:

babunello [35]3 years ago

8 0

It look like a storm is forming out into the ocean and building pressure and maybe become a hurricane.
I hope this helps :)!!!

ser-zykov [4K]3 years ago

3 0

From the picture we can conclude that there's a hurricane forming somewhere above the sea.

In the picture, we can easily see the circular movement and arrangement of the air masses, and that is a sign that a cold (heavier) and warm (lighter) air masses have collided, thus mixing and creating a circular movement. Also we can notice the ''eye'' in the middle, which is a trademark of the hurricanes. So wherever this image may be taken, there's extremely strong winds and intense rainfall.

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Point A of the circular disk is at the angular position θ = 0 at time t = 0. The disk has angular velocity ω0 = 0.17 rad/s at t

statuscvo [17]

Given that,

Angular velocity = 0.17 rad/s

Angular acceleration = 1.3 rad/s²

Time = 1.7 s

We need to calculate the angular velocity

Using angular equation of motion

$\omega=\omega_{0}+\alpha t$

Put the value in the equation

$\omega=0.17+1.3\times1.7$

$\omega=2.38(k)\ m/s$

We need to calculate the angular displacement

Using angular equation of motion

$\theta=\theta_{0}+\omega_{0}t+\dfrac{\alpha t^2}{2}$

Put the value in the equation

$\theta=0+0.17\times1.7+\dfrac{1.3\times1.7^2}{2}$

$\theta=2.1675\times\dfrac{180}{\pi}$

$\theta= 124.18^{\circ}$

We need to calculate the velocity at point A

Using equation of motion

$v_{A}=v_{0}+\omega\times r$

Put the value into the formula

$v_{A}=0+2.38(k) \times0.2(\cos(124.18)i+\sin(124.18)j))$

$v_{A}=0.476\cos(124.18)j+0.476\sin(124.18)i$

$v_{A}=(-0.267j-0.393i)\ m/s$

We need to calculate the acceleration at point A

Using equation of motion

$a_{A}=a_{0}+\alpha\times r+\omega\times(\omega\times r)$

Put the value in the equation

$a_{A}=0+1.3(k)\times0.2(\cos(124.18)i+\sin(124.18)j)+2.38\times2.38\times0.2(\cos(124.18)i+\sin(124.18)j)$

$a_{A}=0.26\cos(124.18)i+0.26\sin(124.18)j+(2.38)^2\times0.2(\cos(124.18)i+\sin(124.18)j)$

$a_{A}=-0.146j-0.215i−0.636i+0.937j$

$a_{A}=0.791j-0.851i$

$a_{A}=-0.851i+0.791j\ m/s^2$

Hence, (a). The velocity at point A is $(-0.267j-0.393i)\ m/s$

(b). The acceleration at point A is $(-0.851i+0.791j)\ m/s^2$

3 0

4 years ago

5. A star begins a s a ball of gas and dust pulled together by

erastova [34]

Answer:

d. Gravity

Explanation:

In the beginning of their lives, stars are formed when clouds of dust and gas are pulled together by gravity.

Hope this helps!!

Please mark as Brainliest

4 0

3 years ago

Study the image.

NNADVOKAT [17]

C. the left plate is positively charged
when looking at these arrows imagine there is a positive electron at the beginning of the arrow. Since the electrons are going towards the plate to the right it is attracted to the negatively charged plate. These electrons want to get away from the positively charged plate because same charges repulse each other

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2 years ago

What type of energy is stored in a stretched spring!?

kondor19780726 [428]

Answer:

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Explanation:

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3 years ago

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