The probability that a randomly selected student is in music/drama is 25%
<h3>How to determine the probability?</h3>
From the table, we have the following values
Music/Drama = 7 + 13 + 5 = 25
Total = (20 + 20 + 25 + 7 + 13 + 5 + 3 + 2 + 5) = 100
The probability is then calculated as:
P = Music/Drama / Total
So, we have:
P = 25/100
Express as percentage
P = 25%
Hence, the probability that a randomly selected student is in music/drama is 25%
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Answer:
(1, 6). The second is (-1 + 2 + 2, 1 + 1 + 1), or (3, 3)
Step-by-step explanation:
Moving from P to Q, we see that x increases by 6 and y increases by 3.
"Trisect" means "divide into three equal subintervals."
We find (1/3) of 6 (which comes out to 2) and (1/3) of 3 (which comes out to 1).
Thus, the first junction (between 1st and 2nd trisection) is (-1 + 2, 5 + 1), or (1, 6). The second is (-1 + 2 + 2, 1 + 1 + 1), or (3, 3)
Answer:
x=2
Step-by-step explanation:
4x-5=3
4x=3+5
4x=8/:2
x=2

Step 1:

Step 2:

On comparing values we get:
Taking:

n-5=0
n=5✓
or
Taking:

n-4=1
n=5✓
The slope of this question is 1/3