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qaws [65]
3 years ago
8

What is the equation of this line? Please Help Y=4x Y=-1/4x Y=-4x Y=1/4x

Mathematics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer: Y=-1/4x

Step-by-step explanation:

A good way to find an equation of a line is to look for the slope. An obvious spot on this line would be when it crosses (0,0), and another one to the right would be when it crosses at (4,-1).

The slope is rise over run, or if we use the two points we found, "rise" would be -1, because it's dropping 1 unit when going from (0,0) to (4,-1), and the "run" would be 4, because it moves to the right 4 from (0,0) to (4,-1).

Putting these two values together we get:

m (slope) = rise / run

m = -1 / 4

Out of all the equations we're given, we can look for the one with a slope of -1/4, which is given to us:

y = (-1/4)x

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Answer:

x=1, y=1. (1, 1). The answer is D).

Step-by-step explanation:

3x-5y=-2

4x-7y=-3

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4(3x-5y)=4(-2)

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y=1

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6 0
3 years ago
What is the value of x? x+15=2x-40
IrinaVladis [17]

Answer:

55 =x

Step-by-step explanation:

x+15=2x-40

Subtract x from each side

x-x+15=2x-x-40

15 = x-40

Add 40 to each side

15+40 = x-40+40

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7 0
2 years ago
Read 2 more answers
X^2 + Y^2 +ax + 2y + 3 = 0<br><br> What number is this equation the equation of a circle?
Sav [38]

Answer:

Eq: (x+a/2)²+(y+1)²=(a²-8)/4

Center: O(-a/2, -1)

Radius: r=0.5×sqrt(a²-8)

Mandatory: a>2×sqrt(2)

Step-by-step explanation:

The circle with center in O(xo,yo) and radius r has the equation:

(x-xo)²+(y-yo)²=r²

We have:

x²+y²+ax+2y+3=0

But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4

And

y²+2y+3=y²+2y+1+2=(y+1)²+2

Replacing, we get:

(x+a/2)²-a²/4+(y+1)²+2=0

(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4

By visual inspection we note that:

- center of circle: O(-a/2, -1)

- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)

6 0
3 years ago
Please help me find the slope thank u
Rzqust [24]
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topjm [15]
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