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qaws [65]
3 years ago
8

What is the equation of this line? Please Help Y=4x Y=-1/4x Y=-4x Y=1/4x

Mathematics
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer: Y=-1/4x

Step-by-step explanation:

A good way to find an equation of a line is to look for the slope. An obvious spot on this line would be when it crosses (0,0), and another one to the right would be when it crosses at (4,-1).

The slope is rise over run, or if we use the two points we found, "rise" would be -1, because it's dropping 1 unit when going from (0,0) to (4,-1), and the "run" would be 4, because it moves to the right 4 from (0,0) to (4,-1).

Putting these two values together we get:

m (slope) = rise / run

m = -1 / 4

Out of all the equations we're given, we can look for the one with a slope of -1/4, which is given to us:

y = (-1/4)x

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Find the value of $x$ that maximizes $$f(x) = \log (-20x + 12\sqrt{x}).$$ If there is no maximum value, write "NONE".
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The function is written as:
f(x) = log(-20x + 12√x)
To find the maximum value, differentiate the equation in terms of x, then equate it to zero. The solution is as follows.

The formula for differentiation would be:
d(log u)/dx = du/u ln(10)
Thus,
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6/√x = 20
x = (6/20)² = 9/100

Thus,
f(x) =  log(-20(9/100)+ 12√(9/100)) = 0.2553

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