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3 years ago

Someone help me plz!!!!

Mathematics

2 answers:

Ad libitum [116K]3 years ago

6 0

Y = 2/3x (the last one)

Annette [7]3 years ago

6 0

y = $\frac{2}{3}$ x is the right answer.

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-11=-7/y PLSSSS HELPPP

Liono4ka [1.6K]

Answer:

7/11

Step-by-step explanation:

$- 11 = \frac{ - 7}{y}$

$= > - 11y = - 7$

$= > y = \frac{ - 7}{ - 11}$

$= > y = \frac{7}{11} (ans)$

4 0

3 years ago

6/8 ÷ 2/3 pleas help me

butalik [34]

Answer:

$\frac{6}{8} \div \frac{2}{3}$

Simplify,

$\frac{6}{8} = \frac{3}{4}$

So now,

$\frac{3}{4} \div \frac{2}{3} \\ = \frac{3}{4} \times \frac{3}{2} \\ = \frac{3 \times 3}{4 \times 2} \\ = \frac{9}{8} \\ = 1.125$

7 0

3 years ago

Simplify ( -12) x ( 13) x (-15) Please give explanation fast please

kherson [118]

Answer:

2340

Step-by-step explanation:

(-12)×(13)×(-15)

=(-156)×(-15)[ (+) × (-) = (-)]

=2340[(-) × (-) = (+)]

5 0

3 years ago

. In the 107th Congress, the Senate consists of 13 women and 87 men. If a lobbyist for the tobacco industry randomly selects thr

brilliants [131]

Answer:

0.18% probability that they are all women

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the senators are chosen is not important, so the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes:

3 women, from a set of 13. So

$D = C_{13,3} = \frac{13!}{3!(13 - 3)!} = 286$

Total outcomes:

3 senators, from a set of 100. So

$T = C_{100,3} = \frac{100!}{3!(100 - 3)!} = 161700$

Probability;

$p = \frac{D}{T} = \frac{286}{161700} = 0.0018$

0.18% probability that they are all women

5 0

3 years ago

Solve for 7 and 8 please

Masteriza [31]

To divide exponents they have to have the same base and then you just subtract the bottom exponent from the top exponent.

7) k × 3^9
----------- =
3^5

k × 3^9-5 =
k × 3^4 =
k × 81 = 81k

8) x^4 × y^10 × 2^11
------------------------ =
y^8 × 2^7

x^4 × y^10-8 × 2^11-7 =
x^4 × y^2 × 2^4 =
x^4 × y^2 × 16=
16x^4y^2

8 0

3 years ago