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kaheart [24]
3 years ago
11

Someone help me plz!!!!

Mathematics
2 answers:
Ad libitum [116K]3 years ago
6 0
Y = 2/3x (the last one)
Annette [7]3 years ago
6 0
y = \frac{2}{3} x is the right answer.

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If f(x) = 2x + 3, what is f(–2)
Lelechka [254]

Answer

see explanation: x=-2=-7

7 0
2 years ago
Read 2 more answers
Which one of the following fractions is equivalent to 1/2? a. 2/4 b. 1/8 c. 1/4 d. 2/8
Whitepunk [10]
2/4 is equivalent to 1/2
6 0
4 years ago
PLEASE HELP DUE IN 2 HOURS!<br><br><br> 4.22 g/cm to lbs/ft
Katarina [22]

Answer:

The answer is 0.28 lbs/ft or 0.3 lbs/ft, if rounded.

Step-by-step explanation:

In order to solve, divide the mass / length value by 14.882.

I hope this helps you.

5 0
3 years ago
Math help please help thanks
ser-zykov [4K]

Answer:

62

Step-by-step explanation:

Draw a line from the bottom of the 4 foot line straight across (horizontally) until it hits the vertical line on your left.

The two lines (the one you drew and the left vertical line) meet at right angles.

The upper figure is a rectangle.

Area = L * W

L = 5

W = 4

Area = 5 * 4

Area = 20

Now the bottom rectangle can be found the same way.

Area = L * W

L = 14

W = 3

Area = 14 * 3

Area = 42

The total area = 42 + 20

Total area = 62.

The comment was correct.

5 0
3 years ago
Weight gain during pregnancy. In 2004, the state of North Carolina released to the public a large data set containing informatio
pychu [463]

Answer:

1. B. H0: μ1−μ2=0, HA: μ1−μ2≠0

2. z=1.2114

3. P-value=0.2257

4. Do not reject H0

Step-by-step explanation:

We have to perfomr an hypothesis test to see if there is strong evidence that there is a significant difference between the two population means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2\neq0

Being μ1 the mean average gain for younger mothers and μ2 the mean average gain for mature mothers.

(NOTE: we are comparing means, not proportions, as it is the random variable is the weight gain).

As we are claiming "strong evidence", the level of significance will be 0.01.

For younger mothers, the sample size is n1=840, the sample mean is 30.7 and  the sample standard deviation is s1=14.91.

For mature mothers, the sample size is n2=132, the sample mean is 29.15 and the sample standard deviation is s2=13.46.

The difference between means is

M_d=\mu_1-\mu_2=30.7-29.15=1.55

The standard error of the difference between means is

s_M=\sqrt{\dfrac{s_1^2}{n_1}+\dfrac{s_2^2}{n_2}}=\sqrt{\dfrac{14.91^2}{840}+\dfrac{13.46^2}{132}}=\sqrt{ 0.2647+1.3725}=\sqrt{1.6372}\\\\\\s_M=1.2795

Then, the statistic can be calculated as:

z=\dfrac{M_d-(\mu_1-\mu_2)}{s_M}=\dfrac{1.55-0}{1.2795}=1.2114

The P-value for this z-statistic in a two tailed test is:

P-value=2P(z>1.2114)=0.2257

As the P-value is greater than the significance level, the null hypothesis failed to be rejected.

There is no enough evidence to claim that the real average weight gain differs from mature and youger mothers.

5 0
3 years ago
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