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3 years ago

List all the even numbers less than 50,

Mathematics

1 answer:

nexus9112 [7]3 years ago

7 0

Step-by-step explanation:

Even numbers less than 50={2,4,6,8,10,12,14,16,18,20,22,24,26,28,30,32,34,36,38,40,42,44,46,48}

Total=24

Multiples of 5={10,20,30,40}

Probability (multiple of 5)=4/24

=1/6

P(between 10 and 30)=12,14,16, 18, 20, 22, 24, 26, 28

Total=9

Probability=9/24

=3/8

Probability is number 12

=1/24

Probability it has square less than 40

=(4,36)

Two numbers

Probability=2/24

=1/12

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The price of an errand as increased from $30 to $35 what is the percantage increased

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Answer:

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2 years ago

In the above figure, the radius of curvature is 10 ft and the height of the segment is 2 ft. What's the length of the chord?

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3 years ago

Solving by the substitution method<br> y=3x+7<br> y-5x+8

Sveta_85 [38]

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2 years ago

Consider the following. f(x) = x5 − x3 + 6, −1 ≤ x ≤ 1 (a) Use a graph to find the absolute maximum and minimum values of the fu

kykrilka [37]

ANSWER

See below

EXPLANATION

Part a)

The given function is

$f(x) = {x}^{5} - {x}^{3} + 6$

From the graph, we can observe that, the absolute maximum occurs at (-0.7746,6.1859) and the absolute minimum occurs at (0.7746,5.8141).

b) Using calculus, we find the first derivative of the given function.

$f'(x) = 5 {x}^{4} - 3 {x}^{2}$

At turning point f'(x)=0.

$5 {x}^{4} - 3 {x}^{2} = 0$

This implies that,

${x}^{2} (5 {x}^{2} - 3) = 0$

${x}^{2} = 0 \: or \: 5 {x}^{2} - 3 = 0$

$x = - \frac{ \sqrt{15} }{5} \: or \: x = 0 \: \: or \: x =\frac{ \sqrt{15} }{5}$

We plug this values into the original function to obtain the y-values of the turning points

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} +750)) \:and \: (0, - 6) \: and\: ( \frac{ \sqrt{15} }{5} , \frac{1}{125} ( - 6 \sqrt{15} +750))$

We now use the second derivative test to determine the absolute maximum minimum on the interval [-1,1]

$f''(x) = 20 {x}^{3} - 6x$

$f''( - \frac{ \sqrt{15} }{5} ) \: < \: 0$

Hence

$( - \frac{ \sqrt{15} }{5} , \frac{1}{125} ( 6 \sqrt{15} + 750))$

is a maximum point.

$f''( \frac{ \sqrt{15} }{5} ) \: > \: 0$

Hence

$( \frac{ \sqrt{15} }{5} , \frac{1}{125} (- 6 \sqrt{15} + 750))$

is a minimum point.

$f''(0) \: =\: 0$

Hence (0,-6) is a point of inflexion

4 0

3 years ago

Erik correctly rounds three numbers. One and StartFraction 7 over 29 EndFraction rounds to 1 One and five-sixths rounds to 2 0.1

Leya [2.2K]

Answer:

From greatest to least

One and five-sixth rounded to 2

One and StartFraction 7 over 29 rounded to 1

0.16 rounded to 0

Step-by-step explanation:

1+7/29=29+7/29

=36/29

=1.24

Approximately

1+5/6=6+5/6

=11/6

=1.83

Approximately

0.16

Approximately =0

From greatest to least

One and five-sixth rounded to 2

One and StartFraction 7 over 29 rounded to 1

0.16 rounded to 0

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2 years ago