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Arlecino [84]
3 years ago
15

If a number is divided by eleven, the solution is two-fifths. What is the number?

Mathematics
2 answers:
Scrat [10]3 years ago
8 0
Let
x----------> the number

we know that
x/11=2/5-----> x=11*2/5-------> x=22/5

the answer is
the number is 22/5
mixer [17]3 years ago
7 0
The number is 4 2/5.

Setting up the equation, we have
x/11 = 2/5

Multiply both sides by 11:
x = 2/5(11) = 2/5(11/1) = 22/5 = 4 2/5
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Q. Friday night’s hockey game was attended by 180 students. This is about 60 % of the school’s population. What is the total pop
OlgaM077 [116]

Answer:

The total population of the school is 300 students.

Step-by-step explanation:

Considering, we are working with percentage we can use the equation:

y = %x.

To fill in the equation you can use what you already know, 60% = 180

180 = 0.60x

To solve this, you can then divide both sides of the equation by 0.60. This will then give you your answer, 300 = x.

For checking, you can do 180 = 0.60(300) which will result in 180 = 180.

7 0
3 years ago
10 points
Mazyrski [523]
I think the answer is d I could be wrong
5 0
3 years ago
Alice weighs 20 dogs and 20 cats. The mean weight for the dogs is 32kg and the mean weight for cats is 4kg. The range in weight
azamat

With the mean and range, we can estimate the weights of the smallest and largest animals in each group.

For cats the interval is [ 3.75kg, 4.25kg] and for dogs is [9.5kg, 54.5kg]

<h3>Which conclusions can be made with the given information?</h3>

We know that the mean weight for cats is 4kg, and the range (difference between the largest value and smallest value) is 0.5kg.

  • From that, we can conclude with some confidence (but not exactly), that the largest cat weights 4kg + 0.5kg/2 = 4.25kg
  • And the smallest cat weights 4kg - 0.5kg/2 = 3.75kg

(Assuming a normal distribution).

Similar for the dogs, the mean weight is 32kg and the range is 45kg, then:

  • The largest dog weights 32kg + 45kg/2 = 54.5kg
  • The smallest dog weights 32kg - 45kg/2 = 9.5kg

(again, assuming a normal distribution).

If you want to learn more about means and ranges:

brainly.com/question/14532771

#SPJ1

3 0
2 years ago
Determine whether the given procedure results in a binomial distribution. If it is not​ binomial, identify the requirements that
Harlamova29_29 [7]

Answer:

Option C is the correct one

Step-by-step explanation:

The events are independent because you are selecting the students randomly and how much they like rap music does not depend on the results on the other students. However, in each event of the binomial distribution there are two possible outcomes: success and fail. In this experiment there are 10 possible results for each event, therefore the distribution inst binomial. The correct answer therefore is C.

6 0
3 years ago
A study on students drinking habits asks a random sample of 60 male UF students how many alcoholic beverages they have consumed
Alex17521 [72]

Answer:

A. (4.78, 6.90)

Step-by-step explanation:

Using the following formulas the lower and upper limits of the Interval are calculated

Lower limit = mean - (standard deviation /√sample size)* Zr

Upper limit = mean + (standard deviation /√sample size)* Zr

Zr depends on confidence interval  and can be found in a z table

Zr for 90% = 1.645

then

Lower limit = 5.84 - (4.98 /√60)* 1.645 = 4.78

Upper limit = 5.84 + (4.98 /√60)* 1.645 = 6.90

8 0
3 years ago
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