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pishuonlain [190]
3 years ago
15

Solve √(2x-5) - √(x+6) = 0.

Mathematics
1 answer:
nika2105 [10]3 years ago
8 0

Answer:

The solution to this question is 11.

Step-by-step explanation:

Given that

√(2x-5) - √(x+6) = 0

√(2x-5) =√(x+6)  equation (1)

square of the equation (1)

(√(2x-5))^2 =(√(x+6))^2

we know that √a*√a=(√a)^2=a.So

2x-5=x+6          after square.

2x-x=6+5                exchange value

x=11  

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Write a formula that will yield the nth term of the sequence: 3,-2,-7,-12
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Answer:

-5n + 8

Step-by-step explanation:

<u>1. What is the difference?</u>

  The sequence goes down by 5. This means that the formula will have -5n in it.

<u>2. Work out the term before the first term.</u>

    The first term is 3, and we know that the sequence goes up by 5. So, to get the term before 3 we would add 5.

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<u>3. Put that term at the end of the equation. </u>

   We have -5n already and we just worked out the term before the first one which is positive 8 - so put that at the end of the equation.

-5n + 8  This is our answer!

Just to prove it works:

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Solve using elimination.<br> 3x − 5y = 18 <br> -10x + 5y = 10
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Add them because the 5y's have the right symbols for us to add

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Divide

x = -4

Now you can plug in -4 for x in one equation, I would use the first equation!

3(-4) - 5y = 18

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Divide

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Since 18 does equal 18 you know that your solution's work!

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