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Nataly_w [17]
3 years ago
14

Please help and explain very easy good luck

Mathematics
2 answers:
Mars2501 [29]3 years ago
7 0

Answer:

-76

Step-by-step explanation:

A positive digit multiplied by a negative digit will result as a negative digit.

So,

6 · -8 = -48

Now if there is a problem where a number is added by a negative digit number, you turn the "plus" sign into a "negative" sign.

So,

- 48 + (- 28)

-48 - 28

If you subtract a negative by a negative, the answer will be negative BUT you have to ADD those two negative digits together and put the negative sign after.

- 48 - 28 = -76

melamori03 [73]3 years ago
5 0

Answer:

-76

Step-by-step explanation:

First multiply, because thats first according to order of operations. 6x-8 is -48. Then add, because that is the only thing left to do. -48+-28=-76

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3 years ago
What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b
kramer

Option C: a=3, b=4 is the value of a and b

Explanation:

Given that the expression \sqrt{648}=\sqrt{2^a\times3^b}

We need to determine the value of a and b

Let us consider the term \sqrt{648} and take the prime factorization of the term 648

Thus, we have,

648 divides by 2,

648=2 \cdot 324

324 divides by 2,

648=2 \cdot 2 \cdot 162

162 divides by 2,

648=2 \cdot 2 \cdot 2 \cdot 81

81 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 27

27 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 9

9 divides by 3,

648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3

Thus, we have,

\sqrt{648}=\sqrt{2^{3} \cdot 3^{4}}

Therefore, equating the powers of 2 and 3, we get,

a=3, b=4

Hence, the value of a and b is 3 and 4

Thus, Option C is the correct answer.

4 0
3 years ago
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Step-by-step explanation:

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Answer:

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