2 years ago

Pls help me with this

1 answer:

Zanzabum2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Tems11 [23]

The slope of the tangent line to $f$ at $x=-1$ is given by the derivative of $f$ at that point:

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}$

Factorize the numerator:

$2x^2-2=2(x^2-1)=2(x-1)(x+1)$

We have $x$ approaching -1; in particular, this means $x\neq-1$ , so that

$\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)$

Then

$f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4$

and the tangent line's equation is

$y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2$

6 0

2 years ago

nevsk [136]

Answer:

the answer is 12

Step-by-step explanation:

7 0

2 years ago

rewona [7]

Atleats 80% an C isn't too shabby for grade improvement 90% will definitely make it sure tho

8 0

3 years ago

lbvjy [14]

It’s brainly find answers to ur questions

6 0

3 years ago

horsena [70]

The sum of their ages is 71+68=149
They are actually 149 years old

7 0

2 years ago