Pls help me with this

A freight train from city A to city B and a passenger train from city B to city A left the cities at the same time, at 10:00 AM,

djyliett [7]

Answer: Both trains would meet at 1 pm

Step-by-step explanation:

Let t represent the time at which both trains will pass each other.

The distance between the cities is 360 miles. This means that by the time both trains meet, the total distance covered would be 360 miles.

Distance = speed × time

The freight train is travelling at 50 mph. Distance covered by the freight train in t hours is 50t.

The passenger train is travelling at 70 mph. Distance covered by the passenger train in t hours is 70t.

Since the total distance covered is 360 miles, it means that

50t + 70t = 360

120t = 360

t = 360/120

t = 3 hours

Both trains would meet at 1 pm

8 0

3 years ago

H(x) = x^2 + 1 k(x) = x – 2 (h + k)(2)=?

likoan [24]

First we will compute the h+k and then multiply the result by 2.
To add polynomials, we add terms whose variables are alike, for example:
we add the coefficients of x^2 together, the coefficients of x together and so on.

Therefore:
h + k = x^2 + 1 + x - 2 = x^2+x-1

Now, we will multiply this answer by 2 to get the final answer:
2(h+k) = 2(x^2+x-1) = 2x^2 + 2x -2

6 0

3 years ago

Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$